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tatuchka [14]
2 years ago
10

The instructor thinks that the students may have answered the questions by guessing, so that the probability that any given answ

er is correct is . Under this null hypothesis, the number of correct answers has a binomial distribution with trials and success probability . Perform a chi-square test of this hypothesis. Can you reject at the level? Use the -value method with the TI- Plus calculator.
Mathematics
1 answer:
Lisa [10]2 years ago
5 0

Answer:

hmmmm if theres choices its B

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6x+7=25 what is the answer if I solve for x​
Alchen [17]
6x+7=25
start off by subtracting 7 from both sides (whole numbers)
6x=18
then divide 6 from both sides
x=3
7 0
2 years ago
Please help I'll pick brainliest answer!
german

if the car depreciates an average of 13% per year after 8 years the value of the car should be about $6558

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8 0
3 years ago
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What is the slope of a line that passes through the points (9,3) and (12,7)
Vesna [10]

Answer:

1 and 1/3 or

Step-by-step explanation:

-4/-3

so the equation is y-y/x-x so

3-7=-4

9-12=-3

-4/-3=4/3 or 1 and 1/3.

4 0
2 years ago
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Solve the system 5x+3y=-9 & -2+y=8
Illusion [34]
X=-39/5 and y=10 :) i hope this helps you out !
5 0
3 years ago
(X^4)-(45x^2)+324 what are the zeroes? And how many turning points?
dmitriy555 [2]

Zeroes:

We must solve

x^4-45x^2+324=0

To do so, we define the auxiliary variable t=x^2. The equation becomes

t^2-45t+324=0

The quadratic formula yields the solutions

t=9,\quad t=36

Substituting back t=x^2 gives

x^2=9 \iff x=\pm 3,\quad x^2=36 \iff x=\pm 6

So, the zeroes are -6, -3, 3, 6.

Turning points:

Turning points are points where a function stops being increasing to become decreasing, or vice versa. Since functions are increasing when their first derivative is positive and decreasing when it's negative, turning points are points where the first derivative is zero.

We have

f(x)=x^4-45x^2+324 \implies f'(x)=4x^3-90x

If we set the derivative to be zero, we have

4x^3-90x=0 \iff x(4x^2-90)=0

So, the derivative is zero if x=0 or

4x^2=90 \iff 2x^2=45 \iff x^2=\dfrac{45}{2}\iff x=\pm\sqrt{\dfrac{45}{2}}

6 0
2 years ago
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