(a^3b)^2 • 4ab^3
a^6b • 4ab^3
4a^6b+1b^3
The expression equivalent to the fort is a) 4(n-3) -6n, if you so the math for the first one do what is inside the parenthesis first. (think PEMDAS) Parenthesis, Exponents, Multiplication, Division, Addition, and Subtraction. So the first thing it gives you is -6n +(-12) Well, a negative + a negative = a negative! So, -6+-12= -18, then add your caroable. So, -18n. Now, you add -18n with what you have left so 4n -18+4 is -14n. So, if you do answer a) (n-3) = (1n-3)= (1-3) =-2. -2×4=-8n because a negative × a positive = a negative because they have different signs. From there you have -8n - (6) Instead of subtracting you just add a negative So, you would rewrite your problem as: -8n+(-6)= -14n the same thing you got as your orginal. Hope tj
his helped! Don't forget about adding you variables and PEMDAS!! Also d po not forget about your positive a negative rules!!!
Evaluate: 2(1/4) + 2/5 ÷ (-1/2) - 1/4
⇛9/4 + 2/5 ÷ (-1/2) - 1/4
Take the LCM of the 4 and 5 is 20.
Again, 2 and 4 is 4.
⇛[(54+8)/20] ÷ [(-2 - 1)/4]
⇛62/20 ÷ (-3/4)
⇛62/20 × 4/-3
⇛62/{5*(-3)}
⇛62/-15.
This is an impossible equation.
If you have something and you add 3 to it, how can the result be the same as the original?
There is no other way to rewrite the expression from fractional form
