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Over [174]
3 years ago
9

How do I solve this?

Mathematics
1 answer:
iren2701 [21]3 years ago
5 0

Answer:

Firstly find the area of the square and then the area of the two triangles and then plus it. That's what I think I tried

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Dr. Pagels is a mammalogist who studies meadow and common voles. He frequently traps the moles and has noticed what appears to b
Rina8888 [55]

Answer:

The food preferences among vole species are independent of one another.

Step-by-step explanation:

The hypothesis can be defined as follows:

<em>H</em>₀: The food preferences among vole species are independent of one another.

<em>Hₐ</em>: There is a relationship between voles and food preference.

The data provided is:

                                           meadow voles            common voles

                 apple slices                15                                   21

peanut butter-oatmeal               25                                    16

A Chi-square test for the Goodness of fit will be used.

The expected values are computed using the formula:

E_{i}=\frac{\text{ith Row Total}\times \text{jth Column Total}}{N}

Consider the Excel sheet attached.

The Chi-square statistic value is 2.861.

Compute the degrees of freedom as follows:

df = (r - 1)(c - 1)

   = (2 - 1)(2 - 1)

   = 1

Compute the <em>p</em>-value as follows:

p-value=P(\chi^{2}_{(1)}>2.861)=\text{CHISQ.DIST.RT(2.861,1)}=0.091

The <em>p</em>-value = 0.091 > <em>α </em>= 0.05

The null hypothesis will not be rejected.

Thus, it can be concluded that the food preferences among vole species are independent of one another.

4 0
3 years ago
Evaluate the following expression when x = 3 and y = 4:<br> 2x + y2 - 1
Nimfa-mama [501]

Answer:

21

Step-by-step explanation:

x = 3

y = 4

2x + y² - 1

2(3) + 4² - 1

2(3) + 16 - 1

6 + 16 - 1

22 - 1

21

4 0
3 years ago
Read 2 more answers
A music industry researcher wants to estimate, with a 90% confidence level, the proportion of young urban people (ages 21 to 35
Maslowich

Answer:

1,539

Step-by-step explanation:

Using Simple Random Sampling in an infinite population (this is such a large population that we do not know the exact number) we have that the sample size should be the nearest integer to

\large \frac{Z^2pq}{e^2}

where

<em>Z= the z-score corresponding to the confidence level, in this case 90%, so Z=1.645 (this means that the area under the Normal N(0,1) between [-1.645,1.645] is 90%=0.9) </em>

<em>p= the proportion of young urban people (ages 21 to 35 years) who go to at least 3 concerts a year= 35% = 0.35 </em>

<em>q = 1-p = 0.65 </em>

<em>e = the error proportion = 2% = 0.02 </em>

Making the calculations

\large \frac{Z^2pq}{e^2}=\frac{(1.645)^2*0.35*0.65}{(0.02)^2}=1,539.09

So, the sample size should be 1,539 young urban people (ages 21 to 35 years)

6 0
3 years ago
Pour connaitre la distance qui la separes dune ile armelle vise un arbre de deux endroit distant de 10m sur une berge elle a pri
QveST [7]

Répondre:

AI = 32,36 m

IE = 30,78 m

Explication étape par étape:

Utilisation de Pythagore:

Cosθ = adjacent / hypoténus

AI = hypoténus

θ = 72 °

Adjacent = 10 m

Cos 72 = 10 / AI

0,3090169 = 10 / AI

AI = 10 / 0,3090169

AI = 32,36 m

De la trigonométrie;

IE = opposé

Adjacent = 10m

Tanθ = opposé / adjacent

Tan 72 = IE / 10

IE = Tan 72 * 10

IE = 3,0776835 * 10

IE = 30,78 m

4 0
3 years ago
The table shows the heights of 40 students in a class.
My name is Ann [436]

Answer:

see below

Step-by-step explanation:

There are 7 students between 120 and 124 so take the median of 122

Multiply the number of students by the median

7 * 122 =854

There are 8 students between 124 and 128 so take the median of 126

Multiply the number of students by the median

8 * 126 =1008

There are 13 students between 128 and 132 so take the median of 130

Multiply the number of students by the median

13 * 130 =1690

There are 9 students between 132 and 136 so take the median of 134

Multiply the number of students by the median

9 * 134=1206

There are 3 students between 136 and 140 so take the median of 138

Multiply the number of students by the median

3 * 138 =414

To find the mean, take the total weight and divide by the number of students

(854+1008+1690+1206+414) = 5172 lbs

7+8+13+9+3 = 40 students

5172/40 =129.3 lbs for the average

This is an estimate because we do not know that the number of students in each category will weight the median on average.  We use the mean as an estimate of their weight.  The median is the middle number of the category.

6 0
3 years ago
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