Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour.
Since the distance of MN is 31 and we have a distance of ML
of h -15 and LN of 2h – 8, therefore
ML + LN = h -15 + 2h – 8 = 31
h = 18
substituting the value of h to the expression for LN
obtaining
LN = 2h – 8
LN = 2(18) – 8
LN = 28
Therefore the length of the segment LN is 28 units
Answer:
i think it may be "A" but i may be wrong sorry if im wrong
Step-by-step explanation:
answer key
78.4
Step-by-step explanation:
Multiply 7 x 4 =28
Then Multiply 28 x 2.8 = 78.4
<em>That's how you get your answer ∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞∞ hope that helps out</em>
Step-by-step explanation:
I am not allowed to answer more than 3 questions. So I will do the first 3.
15a. i) (2/3) = 4/9
ii) (2/3) = 8/27
iii) (2/3) = 16/81
b. The product is small because you are finding the fraction of a fraction.
16. Compared to the factors, the product is less than each fraction. This is because, as stated above, you are trying to find a fraction (a part of the whole) of another fraction. When you multiply a whole number by a fraction, the whole number decreases. The same applies to a fraction.
17a. 0.4 × 0.3 = 0.12
b. 0.4 = 4/10 = 2/5
0.3 = 3/10
3/10 × 2/5 = 6/50
