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Karo-lina-s [1.5K]
3 years ago
7

Escherichia coli is a prokaryotic bacterium. How will Escherichia coli reproduce? A. binary fission B. budding C. mitosis D. reg

eneration?
Mathematics
2 answers:
siniylev [52]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Ostrovityanka [42]3 years ago
3 0

Answer:

A. binary fission

Step-by-step explanation:

Escherichia coli is a prokaryotic bacterium. Escherichia coli reproduce asexually by binary fission. While Escherichia coli is undergoing binary division, the process starts with elongation of the cell. Two similar copies of the bacteria is then replicated followed by the formation of a septum.

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Evaluate. (1/2^−2)+1/2 <br>2 <br>2 1/2<br>4<br>4 1/2
alexdok [17]

Answer:

4 1/2

Step-by-step explanation:

I used PEDMAS  to solve this sorry if it is the incorrect answer

3 0
3 years ago
Read 2 more answers
Simplify the expression. b + 3 + 2b + 6
SOVA2 [1]
D. 3b + 9

because you add the like terms 2b and b which means 1b and add 6 and 3.
3 0
3 years ago
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2 Points
marishachu [46]

Answer:

Option C. Substitute -x for x and simplify f(-x)

Step-by-step explanation:

8 0
4 years ago
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it takes the dryer 45 inutes to dry a load of towels. If the dryer uses 6,750,000 joules of energy to dry the towels, what is th
erastova [34]
Given:
45 minutes
6,750,000 joules

Power(w) = Work(j) / Time(s)

Convert the time from minutes to seconds
1 minute = 60 seconds

45 minutes * 60 seconds/min = 45 * 60 seconds = 2,700 seconds

w = 6,750,000 joules / 2,700 seconds
w = 2,500 watts

The power rating of the dryer is 2,500 watts.
5 0
3 years ago
Solve the system. If there is more than one solution, write the general solution. x + y - 2z = 9 3x + y + 2z = 15 x - 5y + 22z =
Margaret [11]

Answer:

<h2>x = (12-k)/2, y = k, z = (k-6)/4 </h2>

Step-by-step explanation:

Given the system of equation

x + y - 2z = 9 ... 1

3x + y + 2z = 15 ...2

x - 5y + 22z = -27... 3

First let us reduce the system of equation into two with two unknowns.

Subtracting 1 from 3

y-(-5y) + (-2z-22z) = 9-(-27)

y+5y + (-24z) = 9+27

6y-24z = 36 ... 4

Multiplying equation 1 by 3 and subtracting from equation 2

3x + 3y - 6z = 27

3x + y + 2z = 15

On subtracting both;

(3y-y)+(-6z-2z) = 27-15

2y-8z = 12 ... 5

Equating 4 and 5

6y-24z = 36 ... 4

2y-8z = 12 ... 5

Multiplying equation 5 by 3 the equation becomes;

6y-24z = 36 ... 6

6y-24z = 36 ... 7

We can see that equation 6 and 7 are the same;

let y = k

6k - 24z = 36

k - 4z = 6

4z = k-6

z = k-6/4

Substituting y = k and z = k-6/4 into equation 1 to get x

From 1; x + y - 2z = 9 ... 1

x + k -2( k-6/4) = 9

x + k - (k-6)/2 = 9

x = 9+(k-6)/2-k

x = {18+(k-6)-2k}/2

x = (12-k)/2

The solutions to the system of equations are x = (12-k)/2, y = k, z = (k-6)/4 where k is any constant. This shows that the system of equation has infinite solutions.

7 0
3 years ago
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