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3 years ago

Celeste makes a conjecture that the perimeter of a square whose sides are an odd

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

8 0

Answer:

top left

Step-by-step explanation:

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kodGreya [7K]

276.25 hope that helps!!

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3 years ago

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Find the unit rate with the second given unit in the denominator.

Nookie1986 [14]

The answer should be 6/1 or 6.
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3 years ago

Solve the equation using the quadratic formula. Enter each solution in simplest form.

sergeinik [125]

For this case we have the following quadratic equation:

$x ^ 2-4x + 23 = 0$

The solutions will be given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Where:

$a = 1\\b = -4\\c = 23$

Substituting the values we have:

$x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (23)}} {2 (1)}\\x = \frac {4 \pm \sqrt {16-92}} {2}\\x = \frac {4 \pm \sqrt {-76}} {2}\\x = \frac {4 \pm \sqrt {76i ^ 2}} {2}\\x = \frac {4 \pmi \sqrt {76}} {2}\\x = \frac {4 \pmi \sqrt {2 ^ 2 * 19}} {2}\\x = \frac {4 \pm2i \sqrt {19}} {2}\\x = 2 \pm i\sqrt {19}$

We have two roots:

$x_ {1} = 2-i \sqrt {19}\\x_ {2} = 2 + i \sqrt {19}$

ANswer:

$x_ {1} = 2-i\sqrt {19}\\x_ {2} = 2 + i\sqrt {19}$

6 0

3 years ago

Helena lost her marbles. But then she found them and put them in 444 bags with mmm marbles in each bag. She had 333 marbles left

galben [10]

Answer:

y = 444mmm + 333

Step-by-step explanation:

let total marbles = y

putting mmm marbles in 444 bags we have the total in the bags to be 444mmm

but there are 333 marbles left that didnt fit in the bags giving us (+333)

adding them both together

therefore the total marbles will be 444mmm + 333

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3 years ago

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-\dfrac{1}{6} \times \left(-\dfrac{9}{7}\right)− 6 1 ×(− 7 9 )minus, start fraction, 1, divided by, 6, end fraction, times,

sergey [27]

Answer:

$\dfrac{3}{14}$

Step-by-step explanation:

The even number of minus signs means the product will be positive. A factor of 3 can be removed to simplify the product. As usual, the numerator of the product is the product of numerators, and the denominator of the product is the product of denominators.

$-\dfrac{1}{6} \times \left(-\dfrac{9}{7}\right)=\dfrac{1\cdot 9}{6\cdot 7}=\dfrac{3\cdot 3}{3\cdot 14}=\boxed{\dfrac{3}{14}}$

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3 years ago

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