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yawa3891 [41]
2 years ago
11

Why does everyone take too long to answer me!

Mathematics
2 answers:
Anastaziya [24]2 years ago
5 0

Answer:

just been answered lol hahahahahahahah

saveliy_v [14]2 years ago
3 0

What do you need help with?

I could try to help!

You might be interested in
It always confuses me when they make me do the baby steps
fgiga [73]

A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by <em>2</em>.

3x-y=0 → 2(3x-y=0) = 6x - 2y = 0

5x+2y=22


The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22


B. So now we combine them:

6x - 2y = 0

+ + +

5x + 2y = 22

= = =

11x + 0 = 22 ← The answer


C. Now that we have the equation 11x = 22, we solve for x

11x = 22 ← Divide both sides by 11

x = 2 ← The answer


D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:

5(2)+2y = 22

10 + 2y = 22

2y = 12

y = 6


<u>Therefore, the solution to this problem is x = 2 and y = 6</u>


5 0
3 years ago
If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank
strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water (Q), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

Q = \dot Q \cdot \Delta t (1)

Where:

\dot Q - Volume rate, measured in feet per minute.

\Delta t - Time, measured in minutes.

If we know that \dot Q = 2000\,\frac{gal}{min} and \Delta t = 120\,min, then the amount of water is:

Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)

Q = 32160\,ft^{3}

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

Q = \frac{\pi}{4}\cdot D^{2}\cdot h (2)

Where:

D - Diameter, measured in feet.

h - Height, measured in feet.

If we know that Q = 32160\,ft^{3} and h = 12\,ft, then the minimum diameter is:

D^{2} = \frac{4\cdot Q}{\pi\cdot h}

D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }

D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }

D \approx 58.415\,ft

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0
2 years ago
Plz help me with this
shtirl [24]
2x-7y=18 _(1)
-2x+4y=5

11y=23 , Y=23/11 sub in 1

2x-7×23/11=18

2x = 18×11 + 7×23

x = ( 198 + 161 )/2 = 359/2
5 0
3 years ago
3 ounces of cinnamon cost $2.40. if there are 16 ounces in 1 point how much does cinnamon cost per pound
Ksivusya [100]
It would be $12.8 a pound.
4 0
3 years ago
Read 2 more answers
Autumn collected 129 seashells at the beach. What is 129 rounded to the nearest ten ?
skad [1K]
If you rounded off 129 to the nearest ten the answer would be 130
8 0
3 years ago
Read 2 more answers
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