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3 years ago

Please help me on this question!!!

Mathematics

1 answer:

sammy [17]3 years ago

5 0

Answer:

I cannot help you because I didnot know the answer

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Y+1 y+8 y+2 y+7

kipiarov [429]

$\dfrac{y+1}{y+2}+\dfrac{y+8}{y+9}=\dfrac{y+2}{y+3}+\dfrac{y+7}{y+8}$

Write all fractions in terms of a common denominator:

$\dfrac{y+1}{y+2}=\dfrac{(y+1)(y+9)(y+3)(y+8)}{(y+2)(y+9)(y+3)(y+8)}$

$\dfrac{y+8}{y+9}=\dfrac{(y+8)^2(y+2)(y+3)}{(y+2)(y+9)(y+3)(y+8)}$

$\dfrac{y+2}{y+3}=\dfrac{(y+2)^2(y+9)(y+8)}{(y+2)(y+9)(y+3)(y+8)}$

$\dfrac{y+7}{y+8}=\dfrac{(y+7)(y+2)(y+9)(y+3)}{(y+2)(y+9)(y+3)(y+8)}$

Then move all fractions to one side and simplify the numerator:

$\dfrac{(y+1)(y+9)(y+3)(y+8)+(y+8)^2(y+2)(y+3)-(y+2)^2(y+9)(y+8)-(y+7)(y+2)(y+9)(y+3)}{(y+2)(y+9)(y+3)(y+8)}=0$

The numerator dictates when the fraction reduces to 0. The denominator can never be 0, so we know that <em>y</em> cannot take any of the values -2, -9, -3, nor -8.

So the equation reduces to

$(y+1)(y+9)(y+3)(y+8)+(y+8)^2(y+2)(y+3)-(y+2)^2(y+9)(y+8)-(y+7)(y+2)(y+9)(y+3)=0$

Expand the left side; you would end up with

$-6(2y+11)=0$

$2y+11=0$

$2y=-11$

$\implies\boxed{y=-\dfrac{11}2}$

8 0

3 years ago

Choose the correct sign that compares these two numbers.

user100 [1]

Answer:

Step-by-step explanation:

0.115 > o.155 would be the correct way to write this

8 0

3 years ago

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Find the radius of the circle which has the same area

Neko [114]

Answer:

13 cm

Step-by-step explanation:

We can get the answer in the following way:

4 0

3 years ago

Please help!!!!!!!!!!!!!!

GREYUIT [131]

Pay attention here because I'm adding an extra letter to our circle to help keep track of the values in our formula. OUTSIDE of the intercepted arc I'm adding the point E. So the major arc is arc BEG and the minor arc is arc BG. The formula then for us is ∠ $BFG= \frac{1}{2}(arcBEG-arcBG)$ . We just don't have values for the arcs yet. If the measure of the central angle is 4x+238, then the measure of arcBG is also 4x+238. Around the outside of the circle is 360°. So we will use it in an expression. ArcBEG=360-(4x+238). Fitting that into our formula we have $2x+146= \frac{1}{2}[(360-4x-238)-(4x+238)]$ . Doing all the simplifying inside there we have $2x+146= \frac{1}{2}(122-4x-4x-238)$ and $2x+146= \frac{1}{2}(-8x-116)$ . Multiply both sides by 2 to get rid of the fraction: 4x+292=-8x-116. Combine like terms to get 12x = -408 and divide to solve for x. x = -34. Fourth choice down from the top.

3 0

3 years ago

Solve this problem that has a class divided. 0+50x1-60-60x0+10=?

MissTica

$Use\ PEMDAS\\0+\underbrace{50\times1}_{50}-60\underbrace{-60\times0}_{0}+10=0+50-60-0+10\\\\=50-60+10=-10+10=\boxed{0}$

7 0

3 years ago

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