Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;

Seperate the differential equation and solve for the constant C.

You have 100 rodents when:

You have 1000 rodents when:

Answer:
2
Step-by-step explanation:
Answer:
(6x-12)+(8x-4)=180
14x-16=180
14x=196
x=14
Step-by-step explanation:
Answer:
2h and 39mins
Step-by-step explanation:
If you are unsure of these times questions. I suggest you draw a timeline! it helps! Trust me!!
Answer:
the answer is 2.
Step-by-step explanation:
the basic form of this equation is y=mx+c where c is the y intercept and m is the gradient. c=2 so 2 is the y intercept