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3 years ago

Plzz answer this as soon as possible! The graph shows the number of miles two cars travel.

Mathematics

1 answer:

Solnce55 [7]3 years ago

3 0

The answer is 15

From the graph:
Car A traveled 60 miles in one hour
Car B traveled 75 miles in one hour.

Car B travels 15 more miles per hour

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Noah has a total of 47 video games he only buys action games in sports games he has 21 warehousing in the sports games how many

kicyunya [14]

Question is not proper;Proper question is given below;

Noah has a total of 47 video games. he only buys action games and sports games. He has 21 more action games than sports games. how many action games, a, and sports games, s, does he own?

Answer:

Noah has 34 action games and 13 sports games.

Step-by-step explanation:

Given:

Total number of games he has = 47

Let the number of action games be 'a'.

Let the number of sports game be 's'.

So we can say that;

Total number of games he has is equal to sum of the number of action games and the number of sports games.

framing in equation form we get;

$a+s = 47 \ \ \ \ \ eqaution \ 1$

Also Given:

He has 21 more action games than sports games.

so we can say that;

$a=s+21 \ \ \ equation\ 2$

Now Substituting equation 2 in equation 1 we get;

$a+s=47\\\\s+21+s=47\\\\2s+21=47$

Subtracting both side by 21 we get;

$2s+21-21=47-21\\\\2s = 26$

Dividing both side by 2 we get;

$\frac{2s}{2}=\frac{26}{2}\\\\s=13$

Now Substituting the value of 's' in equation 2 we get;

$a=s+21=13+21=34$

Hence Noah has 34 action games and 13 sports games.

4 0

3 years ago

L-3l bigger than l-2l

Naily [24]

Answer:

Yes

Step-by-step explanation:

The absolute value if -3 is 3. The absolute value of -2 is 2. Three is greater than 2

6 0

3 years ago

Read 2 more answers

If I worked 8 hours and 49 minutes but my paycheck was only 97.17$ what was my hourly wage.

ruslelena [56]

Answer:

11.021$

Step-by-step explanation:

49min to hr=49/60=0.816

now total worked hrs =8hr +0.816hr=8.166hr

now 1hr wage =97.17$/total hr(8.166)=11.021$

7 0

3 years ago

A manufacturer is interested in the output voltage of a power supply used in a PC. Output voltage is assumed to be normally dist

Luda [366]

The missing values in the question are shown in bold forms below.

A manufacturer is interested in the output voltage of a power supply used in a PC. Output voltage is assumed to be normally distributed, with standard deviation of 0.25 V, and the manufacturer wished to test $\mathbf{ H_o : \mu = 10 V \ against \ H_1 : \mu \neq 10V}$ , using n = 10 units. Statistical Tables and Charts

(a) The critical region is $\mathbf{\overline X < 9.83}$ or $\mathbf{\overline X < 10.17}$ . Find the value of $\mathbf{\alpha }$

Answer:

∝ = 0.032 (to 3 decimal place)

Step-by-step explanation:

From the given information:

$P(\overline X < 9.83 ) + P( X> 10.17) = \bigg (1- P \bigg ( \dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}} \bigg )< Z< \bigg ( \dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}} \bigg ) \bigg )$

$P(\overline X < 9.83 ) + P( X> 10.17) = \bigg (1- P \bigg ( \dfrac{9.83 - 10}{\dfrac{0.25}{\sqrt{10}}} \bigg )< Z< \bigg ( \dfrac{10.17- 10}{\dfrac{0.25}{\sqrt{10}}} \bigg ) \bigg )$

$P(\overline X < 9.83 ) + P( X> 10.17) = \bigg (1- P \bigg ( \dfrac{-0.17}{\dfrac{0.25}{\sqrt{10}}} \bigg )< Z< \bigg ( \dfrac{0.17}{\dfrac{0.25}{\sqrt{10}}} \bigg ) \bigg )$