I hope this helps you
a=4
b=9
c= -1
disctirminant =b^2-4ac
disctirminant =9^2-4.4. (-1)
disctirminant =97
x1=-9+square root of 97/2.4= -9+square root of 97/8
x2= -9-square root of 97/2.4= -9-square root of 97/8
Answer:
Combine like terms onto one side of the equation
Step-by-step explanation:
You have
-x^2 -4x - 3 = 2x + 5
It seems that we should combine like terms to make this equations smaller.
-x^2 - 4x - 3 - 2x - 5 = 0
-x^2 -6x - 8 = 0
- (x + 2)(x + 4) = 0
x = -2 or x = -4
Answer:
5 ft
Step-by-step explanation:
If all sides are of the same length, we can multiply the value of one side by 3, because a triangle has three sides (and the perimeter is all sides added together), to find the perimeter.
× 3
can be rewritten as 
, so:
× 
The numerator & denominator share a common factor of 3, so:
5 ft is the final answer/perimeter.
hope this helps!
Answer:
t = 7s + 4
Step-by-step explanation:
The goal is to get t alone. So we should move 7s to the other side of the equals to sign. When we move 7s to the other side of the equals to sign the sign changes to -7s. There are no like terms to be collected so the answer should be 7s + 4 for t.
Answer:
The answer is below
Step-by-step explanation:
Calvin school is 2.3 miles directly south of his house. After school, he takes a bus 1.8 miles west of his school to the sport complex.
a) What is the length of a straight line between calvins house and the sports complex? Round to the nearest tenth.
b) Calvin takes piano lessons at a community music school located 3.7 miles directly north of the sports complex. What is the length of a straight line between Calvin's house and the music school? Round to the nearest tenth.
Solution:
a) Calvin school, his house and the sport complex form a right angled triangle. The hypotenuse of the right angled triangle is the length of the line between Calvin's house and the sport complex. Let the length of the line between Calvin's house and the sport complex be x.
Using Pythagoras law for right angled triangle, we get that:
x² = 2.3² + 1.8²
x² = 8.53
x = √8.53
x = 2.9 miles to the nearest tenth
b) This forms a right angled triangle with the hypotenuse = length of a straight line between Calvin's house and the music school. one side of the triangle = 1.8 miles and the other side = 3.7 - 2.3 = 1.4 miles.
Let x = length of a straight line between Calvin's house and the music school. Hence:
x² = 1.8² + 1.4²
x² = 5.2
x = √5.2
x = 2.3 miles to the nearest tenth
