The result of
changing a physical sound wave into an analogous electrical signal using a
transducer (such as a microphone) is called analogue audio. In this system, the rapid electrical level is
directly proportional to the rapid air pressure taken by the transducer. The analogue
signal is then augmented and can be kept on an analogue medium such as tape or transformed
further into a succession of discrete mathematical numbers. The advantages of
using this device is that it yields a subtle sound and is pleasing to the ear
by pushing the signal level and overdriving it. But the disadvantages are
editing it would be tedious and prone to degradation.
Answer:
x = D (M/M-m) 2.41
Explanation:
a) Let's apply Newton's second law to find the summation of force, where each force is given by the law of universal gravitation
F = g m₁m₂ / r²
Σ F = 0
F1- F2 = 0
F1 = F2
We set the reference system in the body of greatest mass (M) the planet
F1 = g m₁ M / x²
F2 = G m1 m / (D-x)²
G m₁ M / x² = G m₁ m / (D-x)²
M (D-x)² = m x²
MD² -2MD x + M x² = m x²
x² (M-m) -2MD x + MD² = 0
We solve the second degree equation
x = [2MD ±√ (4M²D² - 4 (M-m) MD²)] / 2 (M-m)
x = {2MD ± 2D √ (M² + (M-m) M)} / 2 (M-m)
x = D {M ± Ra (2M²-mM)} / (M-m)
x = D (M ± M √ (2-m/M)) / (M-m)
x = D (M / (M-m)) (1 ±√ (2-m/M)
Let's analyze this result, the value of M-m >> 1, so if we take the negative root, the value of x would be negative, it is out of the point between the two bodies, so the correct result must be taken with the positive root
x = D (M / (M-m)) (1 + √2)
x = D (M/M-m) 2.41
b) X = 2/3 D
x = D (M/M-m) 2.41
2/3 D = D (M/(M-m)) 2.41
2/3 (M-m) = M 2.41
2/3 M - 2/3 m = 2.41 M
1.743 M = 0.667 m
M/m = 0.667/1.743
M/m = 0.38
<span>C. Measure the soil's volume and then the volume of water that the soil can absorb.</span>
Explanation:
By Hooke's Law, Fe = kx.
Since Fe = 1.6N and x = 9.2cm - 8cm = 1.2cm,
k = Fe/x = 1.6N/1.2cm = 1.33N/cm.
Answer:
1.4 kg
Explanation:
m1 = 0.7 kg
Let the mass of second block is m.
x1 = x
x2 = 3x
According to the Hooke's law
F1 = - kx1
m1 g = - k x
0.7 g = - k x ..... (1)
When both the blocks are placed
(m1 + m2) g = - k x2
(0.7 + m) g = - 3 k x .... (2)
Divide equation (2) by equation (1), we get
(0.7 + m) / 0.7 = 3
0.7 + m = 2.1
m = 2.1 - 0.7
m = 1.4 kg
thus, the mass of second block is 1.4 kg.