Answer:
The specific heat capacity is q_{L}=126.12kJ/kg
The efficiency of the temperature is n_{TH}=0.67
Explanation:
The p-v diagram illustration is in the attachment
T_{H} means high temperature
T_{L} means low temperature
The energy equation :
= R* 
in(
/
)
The specific heat capacity:
=q_{h}*(T_{L}/T_{H})
q_{L}=378.36 * (400/1200)
q_{L}=378.36 * 0.333
q_{L}=126.12kJ/kg
The efficiency of the temperature will be:
=1 - (
/
)
n_{TH}=1-(400/1200)
n_{TH}=1-0.333
n_{TH}=0.67
Answer:
The magnitude of the magnetic field is 
Explanation:
From the question we are told that
The mass of the rod is 
The distance of separation is 
The current is 
The coefficient of friction is 
Generally for the rod the rod to continue moving at a constant speed
The frictional force must equal to the magnetic field force so
Where 
and 
=> 
substituting values
Sorry, but the given info is insufficient.
<span>The angular magnification is the ratio of the viewing distances. </span>
<span>We assume the greater viewing distance is 26 cm. </span>
<span>But the nearer viewing distance depends on the focal length of Thomas's <relaxed> eye in combination with the glasses. We don't know about his relaxed eye. We'd need to know his far point. </span>
<span>For instance, say his far point is 2.5 m. Then his focal length with glasses = 1/(1/2.5+6.2) m = 15.1515 cm. Magnification = 26/15.1515 = 1.716. </span>
<span>If his far point is at infinity, magnification = 1.612.</span>
Answer:
d = 4 d₀o
Explanation:
We can solve this exercise using the relationship between work and the variation of kinetic energy
W = ΔK
In that case as the car stops v_f = 0
the work is
W = -fr d
we substitute
- fr d₀ = 0 - ½ m v₀²
d₀ = ½ m v₀² / fr
now they indicate that the vehicle is coming at twice the speed
v = 2 v₀
using the same expressions we find
d = ½ m (2v₀)² / fr
d = 4 (½ m v₀² / fr)
d = 4 d₀o
