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Ira Lisetskai [31]
3 years ago
14

The result of changing a physical sound wave into an analogous electrical signal using a transducer (such as a microphone) is ca

lled
Physics
1 answer:
Marina CMI [18]3 years ago
8 0

The result of changing a physical sound wave into an analogous electrical signal using a transducer (such as a microphone) is called analogue audio. In this system, the rapid electrical level is directly proportional to the rapid air pressure taken by the transducer. The analogue signal is then augmented and can be kept on an analogue medium such as tape or transformed further into a succession of discrete mathematical numbers. The advantages of using this device is that it yields a subtle sound and is pleasing to the ear by pushing the signal level and overdriving it. But the disadvantages are editing it would be tedious and prone to degradation.

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a force of 6.0kg gives an acceleration of 2.0m/s/s to the right. What is the force of friction on the block?
Alexxx [7]
The answer is 12 thank me later
4 0
3 years ago
A car is moving at 6 m/s and then accelerates at 1.7 m/s2 for 4.2 seconds. What is the final velocity of the car?
Bad White [126]

Explanation:

Hey there!!

Here,

Initial velocity (u) = 6m/s.

Acceleration (a) = 1.7m/s^2.

Time (t) = 4.2s.

final velocity (v) = ?

We have,

a =  \frac{v - u}{t}

Putting their values,

1.7 =  \frac{v - 6}{4.2}

7.14 = v - 6

v = 7.14 + 6

Therefore, the final velocity is 13.14 m/s.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

5 0
3 years ago
Two charged objects separated by some distance attract each other. If the charges on both objects are doubled with no change in
Serggg [28]

Answer:

(a) The force between them quadruples

Explanation:

According to coulomb's law, initial force between the two charged objects is given as;

F_1=\frac{Kq_1q_2}{r^2}

where;

k is coulomb's constant

q₁ is the charge on the first object

q₂ is the charge on the second object

r is the distance between the two objects

When the charges on both objects are doubled, then;

q₁ = 2q₁

q₂ = 2q₂

Force between the two charged objects will become

F_2 = \frac{K2q_12q_2}{r^2} =  \frac{4Kq_1q_2}{r^2} = 4(\frac{Kq_1q_2}{r^2}) = 4F_1

Therefore, the force between them quadruples

4 0
3 years ago
What is the basic difference between ultraviolet, visible, and infrared radiation?
N76 [4]
To me the basic difference is their frequency and wavelength.

For frequency :
Infrared < visible light < ultraviolet

For wavelength :
Infrared > visible light > ultraviolet
3 0
4 years ago
Which example involves the transformation of chemical energy directly into light energy?
postnew [5]
B) a glow stick , glow sticks are made up of certain chemicals and when they fuse together they start to glow which would be considered as light energy
6 0
3 years ago
Read 2 more answers
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