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Ira Lisetskai [31]
3 years ago
14

The result of changing a physical sound wave into an analogous electrical signal using a transducer (such as a microphone) is ca

lled
Physics
1 answer:
Marina CMI [18]3 years ago
8 0

The result of changing a physical sound wave into an analogous electrical signal using a transducer (such as a microphone) is called analogue audio. In this system, the rapid electrical level is directly proportional to the rapid air pressure taken by the transducer. The analogue signal is then augmented and can be kept on an analogue medium such as tape or transformed further into a succession of discrete mathematical numbers. The advantages of using this device is that it yields a subtle sound and is pleasing to the ear by pushing the signal level and overdriving it. But the disadvantages are editing it would be tedious and prone to degradation.

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The blades in a blender rotate at a rate of 6100 rpm. When the motor is turned off during operation, the blades slow to rest in
MissTica

Answer:

<em>155.80rad/s</em>

Explanation:

Using the equation of motion to find the angular acceleration:

\omega_f = \omega_i + \alpha t

\omega_f is the final angular velocity in rad/s

\omega_i  is the initial angular velocity in rad/s

\alpha is the angular acceleration

t is the time taken

Given the following

\omega_f = 6100rpm

Time = 4.1secs

Convert the angular velocity to rad/s

1rpm = 0.10472rad/s

6100rpm = x

x = 6100 * 0.10472

x  = 638.792rad/s

\omega_f = 638.792rad/s\\

Get the angular acceleration:

Recall that:

\omega_f = \omega_i + \alpha t

638.792 = 0 + ∝(4.1)

4.1∝ = 638.792

∝ = 638.792/4.1

∝ = 155.80rad/s

<em>Hence the angular acceleration as the blades slow down is 155.80rad/s</em>

5 0
3 years ago
What physical feature of a wave is related to the depth of the wave base? What is the difference between the wave base and still
Inessa [10]

Answer:

physical feature of a wave is related to the depth of the wave base is The circular orbital motion

B. The wave base is the depth, and the still water level is the horizontal level

3 0
3 years ago
What is the magnitude of the torque that the axle must apply to prevent the disk from rotating?
mihalych1998 [28]

The required torque at the axle, is given by the difference between the

moments of the applied forces.

The torque required is <u>19.62 N·m counterclockwise</u>

Reasons:

The given parameters are;

Mass of the disk, m = 5.0 kg

Location of the axle = Half the radius of the disk

Diameter of the disk, D = 40 cm = 0.4 m

Applied mass, 0.1 m from the axle = 15 kg

Applied mass, 0.3 m from the axle = 10 kg

Required:

Magnitude of torque at the axle that prevent the disk from rotating

Solution:

Torque needed = Clockwise moment - Counterclockwise moment

Clockwise moment = (10 kg × 0.3 m + 5 kg × 0.1 m) × 9.81 m/s² = 34.335 N·m

Counterclockwise moment = 15 kg × 0.1 m  × 9.81 m/s² = 14.715 N·m

τ + Counterclockwise moment = Clockwise moment

τ + 14.715 N·m = 34.335 N·m

Torque required, τ = 34.335 N·m - 14.715 N·m = 19.62 N·m

Torque required, τ = <u>19.62 N·m counterclockwise</u>

Learn more here:

brainly.com/question/19044661

brainly.com/question/19247046

<em>The probable question drawing obtained from a similar question online is attached</em>

7 0
3 years ago
It takes 160 kj of work to accelerate a car from 24.0 m/s to 27.5 m/s. what is the car's mass?
ankoles [38]
Work-Energy :W = 1/2 m ( Vf^2 -Vo^2 )
Vo = 24.0 m/s Initial speed 
 Vf = 27.5 m/s  Final speed 

W = 1/2 m ( Vf^2 -Vo^2 )
160 kj = 1/ 2 m ( 27.5^2  -24.0 ^2)
160kj =  4680 x m
convert kilo joules to jeoules                     160000 j = 4689 xm
m = 160000 j/4689
m = 34.18 kg
4 0
4 years ago
Earth attracts a person with a gravitational force of 7.0 × 102 newtons. What is the magnitude of the force with which the indiv
ehidna [41]
The best option is B) <span>7.0 × 10² newtons.

</span>If Earth attracts a person with a gravitational force of <span><span>7.0 × 10² </span>newtons, 
the person attracts Earth with a gravitational force of 7.0 × 10² newtons.</span>
5 0
3 years ago
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