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3 years ago

find the solution set of this inequality. Enter your answer in interval notation using grouping symbols. |-2x-3|≤ 3

Mathematics

1 answer:

Ludmilka [50]3 years ago

3 0

Answer:

Inequality form: -3 $\leq$ x $\leq$ 0

Interval Notation: [-3, 0]

Step-by-step explanation:

Isolate the variable by dividing each side by the factors.

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Find the measure of angle B<br> A.95<br> B.48<br> C.15<br> D.12<br> E.84

ryzh [129]

Answer:

Step-by-step explanation:

side AB is congruent to side AX

this means that the angle ∠A = 4x is the same angle as ∠Z

therefore ∠A = ∠Z = 4x

inside angle of a triangle = 180

∠A + ∠B + ∠Z = 180

4x + 7x + 4x = 180

15x = 180

x = 180/15

x = 12

now substitute x = 12 into angle B

∠B = 7x

∠B = 7 (12)

∠B = 84

therefore, the answer is E) 84

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3 years ago

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Second, since both sides are equal, there and infinite solutions.

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3 years ago

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Find a single expression that represents the area of the outer ring of the circle if the area of the whole circle is represented

sp2606 [1]

Answer: The answer is $A_o=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

Step-by-step explanation: Given that the area of the whole circle is represented by the expression

$A_c=25x^2-12x-9.$

We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.

Now, if 'r' represents the radius of the circle, then we have

$A_c=\pi r^2\\\\\Rightarrow \dfrac{22}{7}r^2=25x^2-12x-9\\\\ \Rightarrow r^2=\dfrac{7}{22}(25x^2-12x-9)\\\\\Rightarrow r=\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

Thus, the area of the outer ring is

$A_o=2\pi r=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

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4 years ago