You wrote it there yourself, at the beginning of your question.
You wrote E = I x R
Divide each side by ' I ' : E / I = R
That's what you're asking for. ^
Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277
oh my thats sm stuff ily <8
Here's link to the answer:
tinyurl.com/wpazsebu
Answer:
7 feet
Step-by-step explanation:
Length of one piece of string = 28 feet.
Length of the second string = 42 feet.
Since the number of required pieces was not given but many are required, the greatest length can be determined by;
If the maximum length is 7 feet, then:
the number of pieces from 28 feet long string = 
= 4
Also,
the number of pieces from the 42 feet lone string = 
= 6
Total number of 7 feet strings that she can make = 4 + 6
= 10
Since many pieces are required, the greatest length she can make is 7 feet. If she increase the length to 14 feet, the number of pieces would be 5 which limit the required number.
