Answer:
Step-by-step explanation:
The coordinates of point P are (-1.4,0.6)
Step-by-step explanation:
We are given A coordinate grid shown from negative 2 to positive 2 on x-axis and negative 2 to positive 2 on y-axis. There are 4 grid lines between a whole unit of the grid.
that means each grid has a value of 0.2.
" A point labeled P is shown at the intersection of 7 grid lines to the left of the y-axis and 3 grid lines above the x-axis "
As P lies on the left of the y-axis and above the x-axis hence the x-value will be negative and y-value will be positive.
According to the given information P lies 7 grid lines to the left of y-axis.
i.e. it has x-value -7×0.2= -1.4
and 3 grid lines above the x-axis i.e. it has y-value:
y-value= 3×0.2=0.6
Hence, the coordinates of Point P are (-1.4,0.6).
Click to let others know, how helpful is it
PLEASE MARK AS THE BRAINIEST
Hey I’m sorry but I do not know the answer.
If she goes 75 mph for 2 hours, that's 150 miles altogether. 45 mph for 1 hour is 45 miles, so 150 + 45 is 195 miles.
Answer:
117.5 ft²
Step-by-step explanation:
To find the area of the shaded area, we can find the area of the square, then subtract the areas of the two semicircles.
First, we will find the area of the given square, by using the formula
, multiplying the length and width. The dimensions of this square are 14×14.
14 · 14 = 196
The area of the square is 196 ft².
We can now find the area of the two congruent half-circles. Since they are identical, we can simply find the area of one circle if it was whole. To find the area of a circle, we'll use the formula
. With some simple deduction, we can see that the diameter of the circle is 10 ft, so the radius would be 5 ft long. Plug our values into the formula.
A =
5²
We will use 3.14 for
.
A = 78.5
The area of both the semicircles is 78.5 ft².
Now, we can subtract.
196 - 78.5 = 117.5
The area of the figure is 117.5 ft².
Good luck ^^
Answer:
Step-by-step explanation:
I will assume that the scale factor is 2.5
A'(-5,2.5) True
AB || A'B' True
?? What does ABAB" mean?
A'B' is an enlargement of AB True