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brilliants [131]
3 years ago
9

HELP PLS -- A square is rotated around the y-axis of coordinate plane. Which of the following three-dimensional figures is forme

d? a. cilinder b.circle c.sphere d. cube
Mathematics
2 answers:
Doss [256]3 years ago
7 0
<h3>Answer: A. Cylinder</h3>

The square must be on the y axis in some way, and the square must be oriented such that its sides are parallel to the x and y axis. Rotating said square around the y axis will form a cylinder. Think of a revolving door. The door is the square while it sweeps out a 3D cylinder shape/space as it rotates around. Another example would be a fan or turbine that rotates in a similar fashion.

aksik [14]3 years ago
3 0

Answer:

The Answer is A. a cylinder                          

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You want to buy an item that costs $100. Which of these is the most cost-effective choice for buying the item?
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The answer is C. This would make the total cost 90 dollars without paying for a membership card or shipping.
3 0
2 years ago
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Two different radioactive isotopes decay to 10% of their respective original amounts. Isotope A does this in 33 days, while isot
Andrews [41]

Answer:

The approximate difference in the half-lives of the isotopes is 66 days.

Step-by-step explanation:

The decay of an isotope is represented by the following differential equation:

\frac{dm}{dt} = -\frac{t}{\tau}

Where:

m - Current mass of the isotope, measured in kilograms.

t - Time, measured in days.

\tau - Time constant, measured in days.

The solution of the differential equation is:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where m_{o} is the initial mass of the isotope, measure in kilograms.

Now, the time constant is cleared:

\ln \frac{m(t)}{m_{o}} = -\frac{t}{\tau}

\tau = -\frac{t}{\ln \frac{m(t)}{m_{o}} }

The half-life of a isotope (t_{1/2}) as a function of time constant is:

t_{1/2} = \tau \cdot \ln2

t_{1/2} = -\left(\frac{t}{\ln\frac{m(t)}{m_{o}} }\right) \cdot \ln 2

The half-life difference between isotope B and isotope A is:

\Delta t_{1/2} = \left| -\left(\frac{t_{A}}{\ln \frac{m_{A}(t)}{m_{o,A}} } \right)\cdot \ln 2+\left(\frac{t_{B}}{\ln \frac{m_{B}(t)}{m_{o,B}} } \right)\cdot \ln 2\right|

If \frac{m_{A}(t)}{m_{o,A}} = \frac{m_{B}(t)}{m_{o,B}} = 0.9, t_{A} = 33\,days and t_{B} = 43\,days, the difference in the half-lives of the isotopes is:

\Delta t_{1/2} = \left|-\left(\frac{33\,days}{\ln 0.90} \right)\cdot \ln 2 + \left(\frac{43\,days}{\ln 0.90} \right)\cdot \ln 2\right|

\Delta t_{1/2} \approx 65.788\,days

The approximate difference in the half-lives of the isotopes is 66 days.

4 0
3 years ago
Read 2 more answers
Can some one explain how to answer this
Softa [21]
You would first have to find the area of the other part.

6 0
3 years ago
The median of the values:29,24,30,23,28,18,
joja [24]

Answer:

26

Step-by-step explanation:

18,23,24,28,29,30

(6 in total + 1)/2=3.5.

- the number which is 3.5 is between 24 and 28.

- middle number between these two is 26.

6 0
1 year ago
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2. Suppose over several years of offering AP Statistics, a high school finds that final exam scores are normally distributed wit
nirvana33 [79]

Answer:

By the Central Limit Theorem, the mean is 78, the standard deviation is s = \frac{6}{\sqrt{n}} and the shape is approximately normal.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 78 and a standard deviation of 6

This means that \mu = 78, \sigma = 6

Samples of n:

This means that the standard deviation is:

s = \frac{\sigma}{\sqrt{n}} = \frac{6}{\sqrt{n}}

What are the mean, standard deviation, and shape of the distribution of x-bar for n?

By the Central Limit Theorem, the mean is 78, the standard deviation is s = \frac{6}{\sqrt{n}} and the shape is approximately normal.

6 0
2 years ago
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