Answer:
B. 1
Step-by-step explanation:
-2|3x − 1| = 0
Divide by -2
|3x − 1| = 0
There is only one solution since 3x-1 must equal 0
3x = 1
x = 1/3
Answer:
Step-by-step explanation:
<u>Scientific notation</u>
where:
is any positive or negative <u>whole number</u>.
To convert a number into scientific notation, <u>move</u> the decimal point to the <u>left or right</u> until there is <u>one digit</u> to the left of the decimal point.
The number of times you have moved the decimal point is .
- If the decimal point has moved to the <u>left</u>, is positive.
- If the decimal point has moved to the <u>right</u>, is negative.
To convert 500,000,000,000 into scientific notation, move the decimal point <u>11 places to left</u>, so a = 5. As we have moved the decimal point 11 places to the left, the exponent "n" is 11 and is <u>positive</u>.
To convert 0.00000000005 into scientific notation, move the decimal point <u>11 places to the right</u>, so a = 5. As we have moved the decimal point 11 places to the right , the exponent "n" is 11 and is <u>negative</u>.
Learn more about scientific notation here:
brainly.com/question/28235385
Step-by-step explanation:
we see f(x), which is |x|.
and we see g(x), which is clearly the same basic graph, it is just shifted 3 units down in y direction.
shifts are simply done by keeping the original function definition and then add it subtract a certain constant that then adapts every original functional value.
so, a shift down by 3 units is done by adding -3.
therefore, C is the correct answer (the original f(x) - 3).
Answer:
The domain and range of this relationship is (-∞,∞) and (-∞,∞) respectively.
Step-by-step explanation:
We are given that Carly is traveling to visit family.
She drive distance on first day = x
She drive distance on second day = y
We are also given that Carly is travelling a total of 800 miles.
So,x+y=800
We are supposed to find domain and range of this relationship.
y=800-x
Domain : (-∞,∞)
Range:(-∞,∞)
Hence the domain and range of this relationship is (-∞,∞) and (-∞,∞) respectively.
