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Readme [11.4K]
3 years ago
8

The length of a rectangle is one more than five times its width. If a perimeter is 38, find the dimensions . Show work .

Mathematics
1 answer:
saul85 [17]3 years ago
6 0
x-width\\5x+1-length\\\\2x+2(5x+1)=38\\\\2x+10x+2=38\\\\2x+10x=38-2\\\\12x=36\ \ \ \ \ \ |:12\\\\x=3\\\\5\cdot3+1=15+1=16\\\\Dimensions:\ 3\ and\ 16
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BRAINLIESTT ASAP! PLEASE HELP ME :)
antiseptic1488 [7]

Step-by-step explanation:

\displaystyle y = Acos(Bx - C) + D

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle Phase\:[Horisontal]\:Shift → \frac{-\frac{2}{3}π}{2} = -\frac{π}{3} \\ Period → \frac{2}{2}π = π

Therefore we have our answer.

Extended Information on the trigonometric function

\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|

NOTE: Sometimes, your vertical shift might tell you to shift your graph below or above the <em>midline</em><em> </em>where the amplitude is.

I am joyous to assist you anytime.

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3 years ago
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If y=−3 , then 4+y4y=
Ne4ueva [31]

Answer:

replace the ys with -3 then solve it

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3 years ago
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I need help asap pls and thank you ;)
olga55 [171]

Answer:

\text{Length of AB is }\frac{ah}{a+h}

Step-by-step explanation:

Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.

we have to find the length of AB.

Let the side of square i.e AB is x units.

As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°

⇒ CP||MP||AB

In ΔMNP and ΔCND

∠NCD=∠NMP     (∵ corresponding angles)

∠NDC=∠NPM     (∵ corresponding angles)

By AA similarity rule,  ΔMNP~ΔCND

Also, ΔKAP~ΔKPM by similarity rule as above.

Hence, corresponding sides are in proportion

\frac{ND}{NP}=\frac{CD}{MP} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{AB}{PM} \\\\\frac{ND}{NP}=\frac{x}{h} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{x}{h}\\\\\frac{NP}{ND}=\frac{h}{x} \thinspace\thinspace and\thinspace\thinspace \frac{KP}{KA}=\frac{h}{x}\\\\\frac{PD}{ND}=\frac{h}{x}-1 \thinspace\thinspace and\thinspace\thinspace \frac{AP}{KA}=\frac{h}{x}-1\\

KA(\frac{h}{x}-1)=AP

ND(\frac{h}{x}-1)=PD

Adding above two, we get

(KA+ND)(\frac{h}{x}-1)=(AP+PD)

⇒ (KN-AD)=\frac{x}{(\frac{h}{x}-1)}

⇒ a-x=\frac{x}{(\frac{h}{x}-1)}

⇒ a-x=\frac{x^2}{h-x}

⇒ x^2=ah-ax-xh+x^2

⇒ x(h+a)=ah

⇒ x=\frac{ah}{a+h}

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3 years ago
Evaluate the expression:
FinnZ [79.3K]

Answer:

vw= 22

Step-by-step explanation:

To find the dot product of vw, multiply the corresponding numbers and add them.

v= <3, -8, -3> w= <-4, -2, -6>

vw= (3*-4)+(-8*-2)+(-3*-6)

vw= -12+16+18

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vw= 22

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If the radius of a circle is 5 what is the circumference
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Answer:

31.42

hope this helps

have a good day :)

Step-by-step explanation:

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