Answer:
A(n)=130+13(n-1) ; 86
Step-by-step explanation:
Here is the sequence
130,143,156,169.......
the first term denoted by a is 130 and the common difference denoted by d is second term minus first term
143 - 130 = 13
Hence a=130 and d = 13
Now we have to evaluate to 13th term.
The formula for nth term of any Arithmetic Sequence is
A(n) = a+(n-1)d
Hence substituting the values of a ,and d get
A(n)=130+13(n-1)
To find the 13th term , put n = 13
A(13)=130+13*(13-1)
= 130+13*12
= 130+156
A(13) = 286
Equation of a line is:
y=mx+C
------------------------
We're looking for m as m stands for gradient.
2x-6y=0 (Divide all terms by 2)
x-3y=0
3y=x
y=1/3x
y=1/3x+0
Therefore m=1/3, C=0.
Rational number I believe so
We are given with two equations to find the values of two variables, hence the problem can be solved.
Adding the two equations:
x + y = 12<u>x - y = 10
</u>2x = 22
<u />x =11
y = 1
Answer:
yes
Step-by-step explanation:
