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likoan [24]
3 years ago
11

I need help plzzzzzz

Mathematics
2 answers:
Leviafan [203]3 years ago
8 0
Yes the slope is 2 since it rises by 2 and runs by 1 and 2/1 slope is the same as saying the slope is 2
charle [14.2K]3 years ago
7 0

Answer:

m=2

Step-by-step explanation:

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Find angle ADB of the equation
Aloiza [94]

Answer:

m\angle ADB = 59\°.

Step-by-step explanation:

Given:

\angle BDC = 31\°

We need to find \angle ADB.

Solution:

Now we can see that given figure is a rectangle with diagonals drawn in it.

So by properties of rectangle which states that;

"All angles of a rectangle are 90°."

So we can say that;

\angle A = \angle B = \angle C = \angle D = 90\°

But

\angle D = \angle BDC + \angle ADB

Substituting the values we get;

31\°+\angle ADB = 90\°

Subtracting both side by  by 31 we get;

31\°+\angle ADB -31\°= 90\°-31\°\\\\m\angle ADB = 59\°

Hence m\angle ADB = 59\°.

8 0
4 years ago
SOMEONE HELP ME PLZZZZ
konstantin123 [22]

Answer:

nice

Step-by-step explanation:

4 0
3 years ago
Find the common ratio of the sequence. -4, 8, -16, 32, ...
stellarik [79]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
Describe the transformation of g(x) as it relates to the parent function f(x).
Jet001 [13]

Answer:

Hope this helps

Step-by-step explanation:

g(x)=f(x−h) g ( x ) = f ( x - h ) - The graph is shifted to the right h units. The vertical shift depends on the value of k . When k>0 , the vertical shift is described as: ... g(x)=f(x)−k g ( x ) = f ( x ) - k - The graph is shifted down k units.

6 0
2 years ago
Write a polynomial with rational coefficients having roots 3,3+i and 3-i
Elena L [17]
Part 1: If the roots of a polynomial are a, b, and c, then the factors can be written in the form (x - a), (x - b), and (x - c). In this case, we have (x - 3), (x - [3 + i]), and (x - [3 - i]). The three factors are (x - 3)(x - 3 - i)(x - 3 + i).

Part 2: The two factors with complex terms are (x - 3 - i)(x - 3 + i), and multiplying these terms as a difference of two squares can give:
(x - 3)^2 - i^2 = x^2 - 6x + 9 - (-1) = x^2 - 6x + 10

Part 3: We now multiply (x^2 - 6x + 10) by the remaining factor of (x - 3). This results in the cubic expression:
(x^2 - 6x + 10)(x - 3)
= x^3 - 3x^2 - 6x^2 + 18x + 10x - 30
= x^3 - 9x^2 + 28x - 30
3 0
3 years ago
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