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Doss [256]
4 years ago
13

A circular hot spring has a diameter of 76 meters. Over time, the diameter of the spring decreases by 4 meters. By how many squa

re meters does the area of the hot spring decrease? Use 3.14 for Pi.
( ANSWER QUICK , had to repost since yall aint responding )

And the answer has to be in centimeters.
Mathematics
1 answer:
VikaD [51]4 years ago
7 0

Answer:

<h2>The area of the spring decreases by  370.52*10⁴cm²</h2>

Step-by-step explanation:

The formula for calculating the area of the circular hot spring = \pi r^{2} or \frac{\pi d^{2} }{4}

Initial area of the spring with diameter of 76metres is as shown

= \frac{\pi (76)^{2} }{4} \\= 1444\pi m^{2}

If the diameter of the spring decreases by 4 meters over time, the new diameter after decrease will be 76meters less 4 meters which is 72metres.

New area;

\frac{\pi (72^{2} )}{4}\\ = 1296\pi m^{2}

Decrease in area = 1444πm²-1296πm²

Decrease in area = 148πm²

= 370.53m²

since  1m²=10⁴cm²

then 370.53m² = 370.52*10⁴cm²

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