Tan C- I need help with this pleases help

HELP ME PLEASE IM HAVING SO MUCH TROUBLE....

zysi [14]

Pretty sure it’s B I could be wrong

5 0

3 years ago

A candy store sells chocolate for $7.91 per pound. The piece you want to buy is .17 lbs. how much will it cost

Paul [167]

Answer:

1 piece will cost 2 cents

Step-by-step explanation:

If you divide 7.91 by 0.17, you will get 0.021492, and if you round that up you will get 0.02 which is 2 cents. Now if you want to find the price of more pieces, you can just multiply 2 by however the person needs to buy, and write that as money :)))

5 0

3 years ago

Read 2 more answers

A group of researchers are interested in the possible effects of distracting stimuli during eating, such as an increase or decre

Dmitry [639]

Using the t-distribution, it is found that since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

At the null hypothesis, it is tested if the consumption is not different, that is, if the subtraction of the means is 0, hence:

$H_0: \mu_1 - \mu_2 = 0$

At the alternative hypothesis, it is tested if the consumption is different, that is, if the subtraction of the means is not 0, hence:

$H_1: \mu_1 - \mu_2 \neq 0$

Two groups of 22 patients, hence, the standard errors are:

$s_1 = \frac{45.1}{\sqrt{22}} = 9.6154$

$s_2 = \frac{26.4}{\sqrt{22}} = 5.6285$

The distribution of the differences is has:

$\overline{x} = \mu_1 - \mu_2 = 52.1 - 27.1 = 25$

$s = \sqrt{s_1^2 + s_2^2} = \sqrt{9.6154^2 + 5.6285^2} = 11.14$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{25 - 0}{11.14}$

$t = 2.2438$

The p-value of the test is found using a two-tailed test, as we are testing if the mean is different of a value, with t = 2.2438 and 22 + 22 - 2 = 42 df.

Using a t-distribution calculator, this p-value is of 0.0302.

Since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

A similar problem is given at brainly.com/question/25600813

4 0

3 years ago

Analia is a school district manager. Here are some details about two schools in her district for the last school year:

AfilCa [17]

Answer is in this link:

brainly.com/question/17270742

6 0

2 years ago

I need help with this last question.

blondinia [14]

Answer:

Step-by-step explanation:

length=1 m

base of triangle=10 m

height=5m

volume= 1/2×10×5×1=25 m cube.

slant height l=√(5²+5²)=√50=5√2

slant surface area=2[5√2×1]=10√2

area of front and back=2×1/2(10×5)=50

total surface area=50+10√2≈50+14.14≈64.14 m²

8 0

3 years ago