3 years ago

I have a few questions! what is the gcf for

Mathematics

1 answer:

Harrizon [31]3 years ago

5 0

Answer:

(21 and 54): 3

(55 and 90): 5

(16 and 30): 2

(42 and 91): 7

(66 and 121): 11

Step-by-step explanation:

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zvonat [6]

Answer:

The real solution is $n=6$ .

Step-by-step explanation:

$\cos(\frac{\pi}{2})=0$ while $\sin(\frac{\pi}{2})=1$

So the equation becomes:

$-64=(2(0)+2i(1))^n$

$-64=(0+2i)^n$

$-64=(2i)^n$

We know that $2^6=64$ . So let's see what $n=6$ gives us:

$(2i)^6=64i^6=64i^4i^2=64(1)(-1)=-64$ .

$-64$ is the result we wanted.

$n=6$ is therefore a solution.

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3 years ago

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Answer:

Step-by-step explanation:

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8x-14=34

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hichkok12 [17]

Answer:

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Step-by-step explanation:

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