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scoundrel [369]

3 years ago

6

Which buying method involves ordering a set amount of inventory at regular times? A. Last in first out B. Fixed order C. Just in

time D. Economic order quantity Please select the best answer from the choices provided A B C D

2 answers:

bixtya [17]3 years ago

5 0

Answer:

fixed order

Step-by-step explanation:

Lena [83]3 years ago

4 0

Answer:

Step-by-step explanation:

It’d be C

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A pole that is 3.1 m tall casts a shadow that is 1.57 m long. At the same time, a nearby tower casts a shadow that id 50.5 m lon

hammer [34]

Step-by-step explanation:

an object and its shadow create a right-angled triangle.

2 objects and their shadows at the same time create therefore two similar right-angled triangular

triangles.

that means the angles are the same, and each side length of one triangle correlates to the corresponding side length of the other triangle by the same factor.

so, when we know the factor of one pair of sides, we can calculate the lengths of the others by using the same factor.

therefore,

1.57 × f = 50.5

f = 50.5 / 1.57 = 32.1656051...

the height of the tower is then

3.1 × f = 3.1 × 32.1656051... = 99.7133758... m ≈ 100 m

5 0

2 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

postnew [5]

I cannot help you with the first draging part since it needs to be done form your device.

But I can help you with the expression. Anything to the power of 0 power is equal to 1. Therefore:

$2^{0} = 1$

Hope it helped,

BioTeacher101

7 0

3 years ago

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

2 years ago

Please help me?!?!!?!!??!!?!!!

hjlf

I'm pretty sure it's 114 miles.

4 0

3 years ago

Read 2 more answers

Marisa's car gets an average of 28 miles per gallon of gas. She plans to drive 200 miles today and 220 miles tomorrow. How many

nadezda [96]

Answer:

15

Step-by-step explanation:

Add the total of miles Marisa is going to drive; 200 + 220 = 420

Next, divide the total miles by the average miles Marisa can travel on one gallon of gas; 420 / 28 = 15

(Hope this helps!)

5 0

3 years ago