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stealth61 [152]

3 years ago

6

A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe

ndent trials of the experiment.
n = 50, p = 0.97, x= 48
P(48) =

1 answer:

pantera1 [17]3 years ago

6 0

Do 0.97 x 48 in a character

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Can someone help me solve this problem by factoring.<br> x^2 + 8x + 16 = 0

Pavlova-9 [17]

Factorization: (x + 4)∧2=0

Solutions based on Factorization: x + 4 = 0 ⇒ X∨1 = X∨2 = -4

8 0

3 years ago

Read 2 more answers

Negative 3 over 4 t equals 5

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Answer:

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Step-by-step explanation:

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4 0

2 years ago

F(x)=-9x^2-2x and g(x)=3x^2+6x-9, find (f-g)(x) and (f-g)(-4)

Sergio039 [100]

Answer:

$(f-g)(x) = -12x^{2} - 8x + 9$

(f-g)(-4) = -151

Step-by-step explanation:

To find f-g(x) we subtract the common terms. So

$f(x) = -9x^{2} - 2x$

$g(x) = 3x^{2} + 6x - 9$

(f-g)(x)

$(f-g)(x) = f(x) - g(x) = -9x^{2} - 2x - (3x^{2} + 6x - 9) = -9x^{2} - 2x - 3x^{2} - 6x + 9 = (-9 - 3)x^{2} + (-2 - 6)x + 9 = -12x^{2} - 8x + 9$

(f-g)(-4)

$(f-g)(x) = -12x^{2} - 8x + 9$

We replace x by -4

$(f-g)(-4) = -12(-4)^{2} - 8(4) + 9= -151$

(f-g)(-4) = -151

5 0

3 years ago

Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.

suter [353]

Answer:

$\theta = 30^\circ, 330^\circ$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

Step-by-step explanation:

Given [Missing from the question]

Equation:

$cos\theta = \frac{\sqrt 3}{2}$

Interval:

$0 \le \theta \le 360$

$0 \le \theta \le 2\pi$

Required

Determine the values of $\theta$

The given expression:

$cos\theta = \frac{\sqrt 3}{2}$

... shows that the value of $\theta$ is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

$cos\theta = \frac{\sqrt 3}{2}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{\sqrt 3}{2})$

$\theta = 30$ --- In the first quadrant

In the fourth quadrant, the value is:

$\theta = 360 -30$

$\theta = 330$

So, the values of $\theta$ in degrees are:

$\theta = 30^\circ, 330^\circ$

Convert to radians (Multiply both angles by $\pi/180$ )

So, we have:

$\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}$

$\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}$

$\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}$

$\theta = \frac{\pi}{6}, \frac{11\pi}{6}$

8 0

2 years ago

1 For each line

Elena-2011 [213]

Step-by-step explanation:

I'll do line A for you and you can use the formulas to solve lines B and C yourself, since its good for you to practice doing these questions yourself

a)

The gradient, m, is calculated using m = (y2-y1)/(x2-x1) where x1,x2,y1 and y2 can be any ordered pairs on the line. I'm going to use (4,0) and (7,3) as the 2 points.

m = (3-0)/(7-4) = 3/3 = 1

b)

The y-intercept is where the line intersects with the x-axis. In this case (0,-4)

c)

The equation of a linear line is y=mx+b (or c depending on which country you are from)

y = 1x-4

y=x-4

Now try the other 2 lines yourself!

If this answer has helped you, considered making this the brainliest answer!

5 0

3 years ago