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2 years ago

Question 17

Mathematics

1 answer:

SOVA2 [1]2 years ago

3 0

Answer:

1.8 × 10^10

Step-by-step explanation:

(7.2 × 10 = 72)

(72) ÷ (4 × 10^-9) = 1.8 × 10^10

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Solve the inequality, x - 1 > 6.

Anna11 [10]

Answer:

x > 7

Step-by-step explanation:

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3 years ago

Sherry buys a pair of boots from Rack Room Shoes for $45.00. What is the total amount paid if

Luba_88 [7]

Answer:

Before Tax Price: $45.00

Sale Tax: 7.00% or $3.15

After Tax Price: $48.15

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2 years ago

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A jeweler wants to minimize business costs and has found that the average cost in dollars per necklace is given by C(x)=0.5x^2-7

Vika [28.1K]

Answer:

The maximum cost is 41 dollars per necklace.

Step-by-step explanation:

The average cost in dollars/necklace is given by :

$C(x)=0.5x^2-7x+65.5$ .....(1)

Where

x is the number of necklaces that are created

To maximize the cost, find the value of x by putting dC/dx = 0

$\dfrac{d}{dx}(0.5x^2-7x+65.5)=0\\\\x-7=0\\\\x=7$

Now put the value of x = 7 in equation (1).

$C(x)=0.5(7)^2-7(7)+65.5\\\\=41\ \text{dollars per necklace}$

Hence, the maximum cost is 41 dollars per necklace.

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2 years ago

If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

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3 years ago

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Lilit [14]

Answer:

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Step-by-step explanation:

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2 years ago

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