Please help with this:(
1 answer:
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Convert the worded expression to algebra
let the product = x
(5³) × 25 = x
write 25 as a base of 5 to a power
(5³) × (5²) = x
using the laws of indices
x = 5
= 5⁵
product therefore is = 3125
let the product = x
(5³) × 25 = x
write 25 as a base of 5 to a power
(5³) × (5²) = x
using the laws of indices
x = 5
= 5⁵
product therefore is = 3125
Answer:
is equation of height of rocket.
Option D is correct.
Step-by-step explanation:
Given: A rocket is launched with speed 85 ft/s from a height 28 feet.
Launching a rocket follows the path of parabola. The equation of rocket should be parabolic.
Parabolic equation of rocket is
Formula:
g ⇒ acceleration due to gravity (-32 ft/s)
v ⇒ Initial velocity ()
h ⇒ Initial height ()
h(t) ⇒ function of height at any time t
Substitute the given values into formula
D is correct.
There are many ways to work a problem like this. You can write an equation for the area of the border and solve for its width; you can graph an equation for the border and find its solutions; or you can use a little number sense.
The difference in length and width of the garden area is 4 ft. If the border is uniform, the difference in length and width of the overall area will remain 4 ft. Thus you can look for factors of 140 (the area) that differ by 4.
.. 140 = 1*140 = 2*70 = 4*35 = 5*28 = 7*20 = 10*14
The last two factors listed differ by 4, so we take these as the overall dimensions of the bordered area.
Without the border, the garden area width is 7 ft. With a border on both sides, the garden area width is 10 ft. Then twice the border width is
.. 10 ft -7 ft = 3 ft . . . . twice the border width
The border width is 1.5 ft.
_____
The attached graph shows the solution to
.. (7 +2x)*(11 +2x) -140 = 0
The overall width with a border of width x will be 7 +2x. The overall length with a border of width x will be 11 +2x. The product of these dimensions is the overall area, 140 t^2. When we subtract that area from the product of dimensions, we want the result to be zero. The graphing program easily tells us the value of x that makes the result zero: 1.5 ft.
The difference in length and width of the garden area is 4 ft. If the border is uniform, the difference in length and width of the overall area will remain 4 ft. Thus you can look for factors of 140 (the area) that differ by 4.
.. 140 = 1*140 = 2*70 = 4*35 = 5*28 = 7*20 = 10*14
The last two factors listed differ by 4, so we take these as the overall dimensions of the bordered area.
Without the border, the garden area width is 7 ft. With a border on both sides, the garden area width is 10 ft. Then twice the border width is
.. 10 ft -7 ft = 3 ft . . . . twice the border width
The border width is 1.5 ft.
_____
The attached graph shows the solution to
.. (7 +2x)*(11 +2x) -140 = 0
The overall width with a border of width x will be 7 +2x. The overall length with a border of width x will be 11 +2x. The product of these dimensions is the overall area, 140 t^2. When we subtract that area from the product of dimensions, we want the result to be zero. The graphing program easily tells us the value of x that makes the result zero: 1.5 ft.