Answer:
The value of p at q = 5 is 406.25
Step-by-step explanation:
∵ p varies directly as the cube of q
→ That means p ∝ q³
∴ The equation of variation is p = kq³, where k is the constant of variation
∵ p = 26 when q = 2
→ Use them to find the value of k
∵ 26 = k(2)³
∴ 26 = k(8)
∴ 26 = 8k
→ Divide both sides by 8
∴
∴ 3.25 = k
→ Substitute it in the equation of variation
∴ p = 3.25 q³ ⇒ equation of variation
∵ q = 5
→ Substitute it in the equation of variation to find p
∴ p = 3.25 (5)³
∴ p = 406.25
∴ The value of p at q = 5 is 406.25
we know that
In a right triangle
the value of the cosine is equal to
and the value of the sine is equal to
so
<u>First case</u>
substitute
therefore
The first case is the solution
<u>Second case</u>
substitute
therefore
The second case is not the solution
<u>Third case</u>
<u>Note The hypotenuse cannot be smaller than the adjacent leg or the opposite leg. This problem has errors </u>
substitute
therefore
The third case is not the solution
the solution is the first case
see the attached figure
Solution :
Given
= weight of the first side
= 6 kg = 6000 g
= distance of the first weight from the triangle.
= 3 m = 300 cm
= distance of the first weight from the triangle.
= 600 cm
Let, = weight of the second side
So, x = x
or
= 3000 g
Therefore, the quantity that is used to replace the question mark in order to make the scale balance is 3000 g.
Answer:
5
Step-by-step explanation:
Since both triangles are similar, the ratio of their corresponding side lengths would be equal.
This implies that:
AB/40 = 8/64
Cross multiply
AB*64 = 40*8
AB*64 = 320
AB = 320/64
AB = 5
Answer:
200000
Step-by-step explanation: