Answer:
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Step-by-step explanation:
Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.
Initial velocity u with which the ball is projected upwards = + 120 ft/s
Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²
The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.
Using the formula:
v² - u² = 2 a h,
where
u = initial velocity of the ball = +120 ft/s
v = final velocity of the ball at the highest point = 0 ft/s
a = uniform acceleration acting on the ball = -32 ft/s²
h = height attained
Substituting the values we get;
0² - 120² = 2 × (- 32) h
=> h = 120²/2 × 32 = 225 feet
The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.
I got 7.64 because you round the 3 to 4 since the 7, in the 3rd decimal place is higher than 5
Answer:
not completely sure but I think its B
Answer:
3.33 or 3 1/3
Step-by-step explanation:
1/3 = 0.33
1 / 3 x 22 = 22 / 3
22/3 - 4 = 3.33 or 3 1/3
Answer:
3231360
Step-by-step explanation:
5280 x 612 equals 3231360
