Answer:
5x+9y=-16
Step-by-step explanation:
here is my work although I am not 100 percent sure I am right because,I am learning the same thing as you
-6+1 over 4+5
y+1=-5/9(x+5)
y+1=-5/9x-25/9
y=-5/9x-16/9
5/9+y=-16/9
5x+9y=-16
Answer:
option (a) It will be closer to 30 than to 20
Step-by-step explanation:
Data provided in the question:
For sample 1:
n₁ = 10
variance, s₁² = 20
For sample 2:
n₂ = 15
variance, s₂² = 30
Now,
The pooled variance is calculated using the formula,

on substituting the given respective values, we get

or
= 26.0869
Hence,
the pooled variance will be closer to 30 than to 20
Therefore,
The correct answer is option (a) It will be closer to 30 than to 20
Let "x" represent the weight of the toppings. We know that we can have any number of toppings. This means that one may ask for no toppings at all too.
Now, we have been told that "S" is the weight of the special sundae in kilograms. This definitely included the "mandatory" 2 kilograms of ice cream. Therefore, S will be at-least equal to 2.
Thus, the inequality that describes S, the weight of the special sundae in kilograms at Ping's Ice Cream Palace is given as:
kilograms.
It can be seen that as x increases, S increases too and if an order does not want any toppings in it then the weight of the special sundae will be a minimum of 2 kg which is the weight of the ice cream.
Ok , lots of questions=lower standard of explanation
just answers
5. 8.5 times 10^12
6. 0.001260-7,003,000
7.3.843 times 10^4
9. x=1
10. 7^(x+5)=49^(x+3)
11. 1.03
12. 25,700(0.85)^x
13. 10a√a
14.
![2 x^{2} y^{4} \sqrt[3]{5x^{2}}](https://tex.z-dn.net/?f=2%20x%5E%7B2%7D%20%20y%5E%7B4%7D%20%20%5Csqrt%5B3%5D%7B5x%5E%7B2%7D%7D%20)
15.6√3
16.

17.
![4 \sqrt[3]{x^{2}}](https://tex.z-dn.net/?f=%204%20%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D%20)
18.

19.√109
20. (8,(3/2))
21. 5 units
Answer:
I am not sure if I'm correct, but I got 16
Step-by-step explanation:
lets look at the formula for cylinder volume:
V=π*r^(2)*h
now, lets plug in 64
64=π*r^(2)*h
h=64/(π*r^(2))
Volume of glass cylinder is
V=((0.5r)^2)*(64/(π*r^(2)))*π
V=0.25π*r^(2)*(64/(π*r^(2)))
V=16π*r^(2)/(π*r^(2)
V=16