All categories

2 years ago

How do you express your terms in pi

Mathematics

2 answers:

Margarita [4]2 years ago

7 0

Good question I don’t know my own self

il63 [147K]2 years ago

4 0

Answer:

To express your answer in terms of pi, simply refrain from substituting pi's numerical value for its symbol in the equation. That way, your answer will look like xπ where x is whatever number you come up with, and π is simply a placeholder.

You might be interested in

How do I figure out a mixed percentage number of a whole

seraphim [82]

Sorry not in high school

7 0

2 years ago

The difference between the squares of two consecutive numbers is 23. what are the two numbers?

Ksju [112]

(x+1)^2-x^2=23

x^2+2x+1-x^2=23

2x+1=23

2x=22

x=11

11^2 = 121

x+1 =12

12^2=144

144-121 = 23

4 0

3 years ago

A company has two types of machines, type R and type S. Operating at a constant rate, a machine of type R does a certain job in

SashulF [63]

Answer:

The number of machines to complete job in 2 hours is 6.

Step-by-step explanation:

Using the relation of the rate of each one machine and knowing that adding up both rates.

$Rate R +Rate S= Rate total$

Rate R = $\frac{x}{36}$ 'x' is the job

Rate S = $\frac{x}{18}$ 'x' is the job

So, using the equation of rates

$Rate total =\frac{x}{36} + \frac{x}{18}$

Rate total is going to be a job in 2 hours so = $\frac{1}{2}$

$\frac{1}{2} = \frac{x}{36}+\frac{x}{18}$ adding up

$\frac{1}{2}= x*\frac{3}{36}$ factoring the x

$\frac{1}{2}= x*\frac{1}{12}$ simplifying

x= $\frac{12}{2} \\$

x= 6

3 0

3 years ago

NEED ASAP plz. I will also mark brainiest! Don't just take points, I will report you.

PilotLPTM [1.2K]

Part A:

You may choose the two lines connecting the origin and points A and B, and choose the portion of the space between them.

The line between the origin and A is

$y = 3x$

We want everything below this line (line included), so the first inequality is

$y \leq 3x$

The line between the origin and B is

$y = \dfrac{1}{3}x$

We want everything above this line (line included), so the second inequality is

$y \geq \dfrac{1}{3}x$

Create a system with these two inequalities and you'll have an area including only points A and B

Part B:

To verify the solutions, we can plug the coordinates of A and B in this system and check that we get something true: the coordinates of point A are (1,3), while the coordinates of point B are (3,1). The system becomes:

$A:\begin{cases}3 \leq 3\cdot 1\\3 \geq \frac{1}{3}\cdot 1\end{cases},\quad B:\begin{cases}1 \leq 3\cdot 3\\1 \geq \frac{1}{3}\cdot 3\end{cases}$

Which means

$A:\begin{cases}3 \leq 3\\3 \geq \frac{1}{3}\end{cases},\quad B:\begin{cases}1 \leq 9\\1 \geq 1\end{cases}$

And these are all true. So, the system is satisfied, which means that the points belong to the shaded area.

Part C

If you draw the line, you'll see that the only points that lay below the line are B and C. In fact, if we plug the coordinates we have

$B:\ 1$

And this are both true. You can check the coordinates of all other points, and see that they won't satisfy the inequality y<3x-6

3 0

2 years ago

HELP ASAP its due today also please include the work if possible

castortr0y [4]

Use photomath. it shows the work too

6 0

3 years ago