The angle of B is 56.2 degrees
<em><u>Solution:</u></em>
Given is a right angled triangle ABC
From given figure,
AB = 9
CB = 5
We have to find the angle of B
Let the angle of B be 
By definition of cosine,

Here, adjacent = CB and hypotenuse = AB
Therefore,

Taking cos inverse on both sides,

Thus the angle of B is 56.22 degrees
Answer:
Number 2
Step-by-step explanation:
Answer:
Definition of right angel
Step-by-step explanation:
right angels is 90
Use the equation
t = -b / (2a)
where:
a = -16
b = 30.4
Plug these values into the equation.
b)
Evaluate h(t) at the time of maximum height. The time of maximum height is the value found in previous part.
c)
Set h(t) equal to 3 and solve for t.
3 = -16t2 + 30.4t + 5
0 = -16t2 + 30.4t + 2
Solve this quadratic equation for t. I suggest you use the quadratic formula to solve for.
t = time
Multiply the acceleration by time and add to the height:
The equation becomes H(t) = -16 * t^2 + 90
set h(t) to 0
0 = -16*t^ +90
Subtract 90 from both sides:
-90 = -16*t^2
divide both sides by -16:
t^2 = -90 / -16
t^2 = 5.625
t = √5.625
t = 2.37 seconds, round to 2.4 seconds.