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3 years ago

Six more than the product of 5 and a number x is -4

Mathematics

2 answers:

ololo11 [35]3 years ago

7 0

Answer:

5x+6 =-4

x = -2

Step-by-step explanation:

product of 5 and a number x

six more than

5x+6

is means equal

5x+6 =-4

Subtract 6 from each side

5x+6-6 = -4-6

5x= -10

Divide by 5

5x/5 = -10/5

x= -2

NISA [10]3 years ago

7 0

Answer:

5x+6 =-4

x = -2

Step-by-step explanation:

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Read 2 more answers

Consider the equation below (in screenshot)

frozen [14]

The approximate solution of the equation shown in the picture is x ≈ 39 / 8 (Right choice: B).

<h3>How to find an approximate solution of a one-variable equation</h3>

The solution of the equation is between x = 4 and x = 5. Now we begin by evaluating each side of the expression (f(x) = x² - 5 · x + 4, g(x) = 2 / (x - 1)) at the average of x = 4 and x = 5.

x = (4 + 5) / 2

x = 4.5

f(4.5) = 4.5² - 5 · 4.5 + 1

f(4.5) = - 5 / 4

g(4.5) = 2 / (4.5 - 1)

g(4.5) = 4 / 7

The solution of the equation is between x = 4.5 and x = 5, then we evaluate at the average:

x = (4.5 + 5) / 2

x = 4.75

f(4.75) = 4.75² - 5 · 4.75 + 1

f(4.75) = - 3 / 16

g(4.75) = 2 / (4.75 - 1)

g(4.75) = 8 / 15

The solution of the equation is between x = 4.75 and x = 5, then we evaluate at the average:

x = (4.75 + 5) / 2

x = 4.875

f(4.875) = 4.875² - 5 · 4.875 + 1

f(4.875) = 25 / 64

g(4.875) = 2 / (4.875 - 1)

g(4.875) = 16 / 31

The approximate solution of the equation shown in the picture is x ≈ 39 / 8 (Right choice: B).

To learn more on successive approximations: brainly.com/question/27191494

#SPJ1

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2 years ago

According to a survey, 60 % of the residents of a city oppose a downtown casino. Of these 60 % about 8 out of 10 strongly opp

katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

Step-by-step explanation:

(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino.

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

Probability that a radomly selected resident opposes the casino: P(A)

Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the probability that a radomly selected resident opposes the casino, P(A)

Probability = number of favorable outcomes / number of possible outcomes

P(A) is given as 60%, which in decimal form is 0.60

ii) Next, determine,the probability that a resident who opposes the casino strongly opposes it, P(B/A):

It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or intersection: P(A∩B).

So, you can use the definition of conditional probability:

P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

P(A∩B) = P(B/A)×P(A) = (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that a radomly selected resident who opposes the casino does strongly oppose the casino, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the casino.

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3 years ago