true or false , the best way to represent all the solutions to a linear inequality is to graph a single line through the x inter
1 answer:
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So the rate of change can be found in different places.
For the first one:
This equation is in slope-intercept form, or y = mx + b.
m would be the slope/rate of change, and b the y intercept. (x and y would just be any sets of ordered pairs that fit into the equation.)
So if you look at which number is in the m spot, or the rate of change spot, you see that 5 is the rate of change.
For the second one: The formula for slope is:
m =
So just put in any ordered pairs in. I'm just going to put in the ordered pairs, (6, 30) and (4, 22).
Or,
m = (30 - 22) / (6 - 4)
Or,
m = 8/2
Or 4.
For the third one:
You can use the same formula as I stated above.
So you have to look for two ordered pairs here, two points.
So you can estimate that two of the points are: (0, 3) and (-2, -9).
So then just solve for that.
(-9 - 3) / (-2 - 0) = -12 / -2 = 6
For the last one:
Again, use the same equation.
m = (7 - 1) / (-1 - (-3))
m = 6/2
m = 3
So the one with the greatest rate of change would be C.
For the first one:
This equation is in slope-intercept form, or y = mx + b.
m would be the slope/rate of change, and b the y intercept. (x and y would just be any sets of ordered pairs that fit into the equation.)
So if you look at which number is in the m spot, or the rate of change spot, you see that 5 is the rate of change.
For the second one: The formula for slope is:
m =
So just put in any ordered pairs in. I'm just going to put in the ordered pairs, (6, 30) and (4, 22).
Or,
m = (30 - 22) / (6 - 4)
Or,
m = 8/2
Or 4.
For the third one:
You can use the same formula as I stated above.
So you have to look for two ordered pairs here, two points.
So you can estimate that two of the points are: (0, 3) and (-2, -9).
So then just solve for that.
(-9 - 3) / (-2 - 0) = -12 / -2 = 6
For the last one:
Again, use the same equation.
m = (7 - 1) / (-1 - (-3))
m = 6/2
m = 3
So the one with the greatest rate of change would be C.
