Line A: y=1/2x + 2
1 answer:
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Answer:
the graph on the right-top
Step-by-step explanation:
Transferring an "x" to the right side in , we get
The system of inequalities is
We have y=2x+2 - ascending function with a=2, b=2
b=2 shows that ascending function intersects Y-axis is in y=2 - that situation is only on the right-top and left-down. So, we refuse left-top and right-down.
y=-x-3 - descending function with a=-1, b=-3
y<2x+2 is an area below the ascending function and we see that on the left-
is an area above the descending function
On the left-down we have an area above both functions, so we refuse this picture
Right-top is correct
Fill your inequality in with the y and x provided and then do the math. (4, -1) would fill in like this (I will use brackets to indicate absolute value symbols, since there are none in the equation editor): ![-1\ \textgreater \ [4]-5](https://tex.z-dn.net/?f=-1%5C%20%5Ctextgreater%20%5C%20%5B4%5D-5)
The right side is in fact equal to the left side so that's not the answer. For (-1, -4): ![-4\ \textgreater \ [-1]-5](https://tex.z-dn.net/?f=-4%5C%20%5Ctextgreater%20%5C%20%5B-1%5D-5)
and these are also equal. Let's try C now (-4, 1): ![1\ \textgreater \ [-4]-5](https://tex.z-dn.net/?f=1%5C%20%5Ctextgreater%20%5C%20%5B-4%5D-5)
. The absolute vale of -4 is 4 so 4 - 5 = -1 which is, in fact, less than 1. So C is our answer.