2 years ago

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1 answer:

8 0

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2 years ago

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Oduvanchick [21]

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Step-by-step explanation:

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Factorize the following algebraic expression:

Hoochie [10]

X^2+16-38=0
find what 2 numbers multiply to get -38 and add to get 16
find factors of 38
2 times 19
there is no way to use common factor so use quadratic formula which is
x= $\frac{ -b+\sqrt{b^2-4ac} }{2a}$ or x= $\frac{ -b-\sqrt{b^2-4ac} }{2a}$

ax^2+bx+c=0 subsitte
a=1
b=16
c=-38
subsitute
$\frac{ -16+\sqrt{16^2-4(1)(-38)} }{2(1)}$ = $\frac{ -16+\sqrt{256+152} }{2}$ = $\frac{ -16+\sqrt{408} }{2}$ = $\frac{ -16+2\sqrt{102} }{2}$ = $-8+\sqrt{102}$
so the answers for x are $-8+\sqrt{102}$ and $-8-\sqrt{102}$ which are aprox -2.099504938362 and +18.099504938362
so it would be
(x-[-8+√102])(x+[8+√102])=0

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How to find solution to system of equations using substitution?

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