Question

A chemist prepares a solution of potassium iodide (KI) by measuring out 88. umol of potassium iodide into a 200. mL volumetric flask and filling the flask to
the mark with water.
Calculate the concentration in mol/L of the chemist's potassium iodide solution. Round your answer to 2 significant digits.


Please Help me!

Answer 1

The concentration in mol/L of the chemist's potassium iodide solution : = 4.4 x 10⁻⁴ M

Further explanation

Given

88. μmol of Potassium iodide

200. mL volumetric flask

Required

The concentration

Solution

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}$

Conversion :

88. μmol = 88 . 10⁺⁶ mol = 8.8 10⁻⁵ mol

200 ml = 0.2 L

The molarity :

= n : V

= 8.8.10⁻⁵ : 0.2

= 4.4 x 10⁻⁴ M