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Answer: The number of N atoms in 137.0 g of N2O3 21.67 x 10∧23 atoms.
Explanation:
- We must obtain the number of moles of the compound: (n = mass/molar mass), mass = 137.0 g and molar mass of N2O3 = 76.01 g/mol.
- n = (137.0 g)/ (76.01 g/mol) = 1.80 mol.
- It is necessary to determine the number of molecules of this sample.
- Every mole contains Avagadro's number (6.02 x 10^23) of molecules.
- The number of molecules = (6.02 x 10^23)(1.80) = 10.84 x 10∧23 molecules.
- Every molecule of N2O3 contain 2 atoms of N.
- The number of N atoms in 137.0 g of N2O3 = (10.84 x 10∧23 molecule) (2 atoms) = 21.67 x 10∧23 atoms.
21/4 * 4 * 2/3
21 * 2/3
42/3 = 14
Answer:
Explanation:
From the information given, we are to show the product of the reaction between the alcohol (stick formula) with pyridinium chlorochromate. The reaction starts with the nucleophilic addition of Cr with oxygen molecule on the alcohol. Then, deprotonation of oxygen occurs, this process is followed by the removal of hydrogen ion to yield the final product. The reaction mechanism can be seen from the attached image below.
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