Answer:
Step-by-step explanation:
2,4,5
Answer:
A. Quantizing error
Step-by-step explanation:
Quantizing error is also known as Distortion. It is the contrast that exists between an analog signal and the digital value which is the closest at each sampling instant from the A/D converter. Quantizing error occurs when there is inaccurate representation of an analog signal which is a result of the resolution of the process adopted in digitizing it.
The resolution of A/D converter determines the quantization error, when the resolution of A/D converter is high, quantization error will be low as well as the quantization noise.
Answer:
144
Step-by-step explanation:
Remark
Well you could do this the brute force way. 32 is the nineth term in the series. Sum = 0 + 4 + 8 + 12 + ... 32 = 144. That will get you an answer.
This works unless you are asked for the 44434th term. Then you better use a formula. Even the hundredth term would be trouble.
Step One
Find d
d is given as 4
Step 2
find n. There are 9 terms. The 9 is given.
Step 3
Find the ninth term.
<em><u>Givens</u></em>
a1 = 0
n = 9
d = 4
<em><u>Formula for the 9th term: </u></em>a9 = a1 + (n - 1)*d
Substitute and Solve
a9 = 0 + (9 - 1)*4
a9 = 8*4 = 32
Step 4
Find the sum of the first 9 terms
Sum = (a1 + a9)*n/2
Sum = (0 + 32)*9/2
Sum = 32 * 9/2
Sum = 32 * 4.5
Sum = 144
Answer:
a. Amplitude: 4
Period: 1
b. The maximum values occur at
The minimum values occur at
The zeros occur at
Step-by-step explanation:
We can see from the graph that;
.
This implies that;
.
The amplitude is 4.
The function also completed one full cycle on the interval [0,1]
The period is
The maximum values occur at
The minimum values occur at
The zeros occur at
This is where the graph intersected the x-axis.
Hey There!! ~
The answer to this is: the upper bound for the length is Lower and Upper Bounds
The lower bound is the smallest value that will round up to the approximate value.
The upper bound is the smallest value that will round up to the next approximate value.
Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.
Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:
As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :
⇒
21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is
Hope It Helped!~
~