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allochka39001 [22]
3 years ago
5

The figure to the right has its Congruent segments marked. AB=__ meters

Mathematics
1 answer:
Ber [7]3 years ago
7 0

9514 1404 393

Answer:

  20 meters

Step-by-step explanation:

The single hash mark on AB matches the single hash mark on AC, so AB = AC. AC is marked as 20 meters, so AB is 20 meters.

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Find the mode of the data.<br> 1, 2, 1, 3, 3, 4, 1<br> The mode is
drek231 [11]

Answer:

1 is the answer.

Step-by-step explanation:

The mode of a data set is the number that occurs most frequently in the set.

5 0
2 years ago
Read 2 more answers
PLEASE ANSWER QUICKLY
Luba_88 [7]
29-11=18
18²+18²=p²
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That's your answer.
6 0
3 years ago
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2x+3y=1 and y=-2 - 9 solve using linear combination method. Please explain steps.
kaheart [24]

Answer:

x=17

Step-by-step explanation:

2x+3y=1

y=-2-9

  • In order to combine these two equations, an idea you need to keep in mind is finding a way of setting these equations as equal to each other. I saw that each equation shared a common value, y. In this case, we need to isolate y in the first equation so that both equations =y.

2x+3y=1

3y=-2x+1

\frac{3y}{3}=\frac{-2x+1}{3}

y=-\frac{2}{3}x+\frac{1}{3}

  • With this, we now know that both -2-9 and -\frac{2}{3}x+\frac{1}{3} are equal to y, so we can set them equal to each other.

y=-\frac{2}{3}x+\frac{1}{3}

y=-11

-\frac{2}{3}x+\frac{1}{3}=-11

  • Reply to this if anything I'm saying or doing is confusing in any way, or if you find a mistake. :) Solve for x.

-\frac{2}{3}x+\frac{1}{3}=-11

-\frac{2}{3}x=-11-\frac{1}{3}

-\frac{2}{3}x =-\frac{33}{3}-\frac{1}{3}

-\frac{2}{3}x =-\frac{34}{3}

-\frac{2}{3}x(-\frac{3}{2})=-\frac{34}{3}(-\frac{3}{2})

x=\frac{102}{6}=17

x=17

  • Hopefully this answer is correct AND makes sense in terms of how I achieved it. Again, reply to this with any questions or mistakes I made and I'll do my best to answer or fix them.

 

4 0
3 years ago
Across which axis was point A reflected​
Snezhnost [94]

Answer:

When point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

i.e A'(0, 1) is the image of point A after a reflection.

Hence, point A is reflected across the x-axis.

Step-by-step explanation:

When we reflect a point A across the x-axis, the value of 'y' gets negated, but the value of 'x' remains unchanged.

In other words, when point P with coordinates (x, y) is reflected across the x-axis and mapped onto point P', the coordinates of P' will be (x, -y).

Thus, the rule is:

P(x, y) → P'(x, -y)

Thus, when point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).

i.e A'(0, 1) is the image of point A after a reflection.

Hence, point A is reflected across the x-axis.

4 0
3 years ago
GUYS PLEASE HELPP PLSPLSOLSOAKGDJXG​
ladessa [460]

Answer:

Let S = starting point

Let ST = length of tunnel

SR = 1414 m

RT = 2236 m

Set up:

ST^2 + SR^2 = RT^2

ST^2 + (1414)^2 = (2236)

Solve for RT to find your answer.

Step-by-step explanation:

5 0
2 years ago
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