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AleksandrR [38]
3 years ago
11

3. Which term has a coefficient of 1? k^7 2x^1 10p 7y^2

Mathematics
1 answer:
lozanna [386]3 years ago
5 0

Answer:

k^7 I hope this will help you

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Calculate the area of each circle
Triss [41]

Answer:

1.54 in²

Step-by-step explanation:

Given that,

→ Radius (r) = 0.7 in

Formula we use,

→ πr²

The area of the circle will be,

→ πr²

→ (22/7) × 0.7 × 0.7

→ (22/7) × 0.49

→ [ 1.54 in² ]

Hence, area of circle is 1.54 in².

8 0
3 years ago
In an election, 471 people voted. Candidate B received 2/3 of the votes. How many votes did Candidate B receive?
dezoksy [38]

Answer:

Step-by-step explanation:

471/3 * 2 = 314

5 0
4 years ago
Read 2 more answers
A leprechaun places a magic penny under a​ girl's pillow. The next night there are 2 magic pennies under her pillow. Each night
viktelen [127]

Answer:

$665.36

Step-by-step explanation:

2^16 or...

2x2x2x2x2x2x2x2x2x2x2x2x2x2x2x2 = 66536 pennies

3 0
4 years ago
Write the equation of the circle with center (−1, −3) and (−7, −5) a point on the circle.
Pepsi [2]
So, we know the center is at -1, -3, hmmm what's the radius anyway?

well, the radius will be the distance from the center to any point on the circle, it just so happen that we know -7, -5 is on it, thus

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ -1 &,& -3~) 
%  (c,d)
&&(~ -7 &,& -5~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
r=\sqrt{[-7-(-1)]^2+[-5-(-3)]^2}\implies r=\sqrt{(-7+1)^2+(-5+3)^2}
\\\\\\
r=\sqrt{36+4}\implies r=\sqrt{40}\\\\
-------------------------------

\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{-1}{ h},\stackrel{-3}{ k})\qquad \qquad 
radius=\stackrel{\sqrt{40}}{ r}
\\\\\\\
[x-(-1)]^2+[y-(-3)]^2=(\sqrt{40})^2\implies (x+1)^2+(y+3)^2=40
5 0
3 years ago
Proving That All Circles Are Similar
Nitella [24]

Answer:

Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another. In our attempt to prove all circles are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.

Step-by-step explanation:

4 0
3 years ago
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