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Find m∠BOC, if m∠MOP = 110°.
Answer:
m∠BOC= 40 degrees
Step-by-step explanation:
A diagram has been drawn and attached below.
- OM bisects AOB into angles x and x respectively
- ON bisects ∠BOC into angles y and y respectively
- OP bisects ∠COD into angles z and z respectively.
Since ∠AOD is a straight line
x+x+y+y+z+z=180 degrees
![2x+2y+2z=180^\circ](https://tex.z-dn.net/?f=2x%2B2y%2B2z%3D180%5E%5Ccirc)
We are given that:
m∠MOP = 110°.
From the diagram
∠MOP=x+2y+z
Therefore:
x+2y+z=110°.
Solving simultaneously by subtraction
![2x+2y+2z=180^\circ](https://tex.z-dn.net/?f=2x%2B2y%2B2z%3D180%5E%5Ccirc)
x+2y+z=110°.
We obtain:
x+z=70°
Since we are required to find ∠BOC
∠BOC=2y
Therefore from x+2y+z=110° (since x+z=70°)
70+2y=110
2y=110-70
2y=40
Therefore:
m∠BOC= 40 degrees
Answer: 1/4
Step-by-step explanation:
In a stack of 24, the 2 mediums are odd and even cards in this question. This means that 1/2 the cards are even and 1/2 are odd. To get a even card once is a 1/2 chance, then to get it again is 1/2 x 1/2 chance or 1/4 chance. This is what I think.
Answer:
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Step-by-step explanation: