num%2==1
The modulo operator (%) divides the left hand side by the right hand side and returns the remainder. When dividing an odd number by 2 there will always be a remainder of 1.
Answer:
import regex as re
def in_parentheses(a_string):
regeX = re.compile(".*?\((.*?)\)")
result = re.findall(regeX, a_string)
return str(result).replace("[","").replace("]","")
print("test 1: "+in_parentheses("Open ( only"))
print("test 2: "+in_parentheses("This is a sentence (words!)."))
The answer is D. All the other answers describe what a budget CAN be like, not necessarily what it is for everyone, if that makes sense.