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garri49 [273]
3 years ago
11

1. Which of the following is required to create a computer simulation?

Computers and Technology
1 answer:
Sonbull [250]3 years ago
6 0
1. Data
2. Input
3. Experimentation
4. Calculates Physics
5. You owe me.
6. Do your work next time.
7. You will never be able to enjoy a nice pipe and gin and use an app like this like a trivia game if you don't force yourself to completely understand your work.
8. I sound like your dad.
9. I am right.
You might be interested in
Use the following cell phone airport data speeds​ (Mbps) from a particular network. Find P10. 0.1 0.1 0.3 0.3 0.3 0.4 0.4 0.4 0.
sasho [114]

Answer:

P_{10} =0.1

Explanation:

Given

0.1, 0.1, 0.3, 0.3, 0.3, 0.4, 0.4, 0.4, 0.6, 0.7, 0.7, 0.7, 0.8, 0.8

Required

Determine P_{10}

P_{10} implies 10th percentile and this is calculated as thus

P_{10} = \frac{10(n+1)}{100}

Where n is the number of data; n = 14

P_{10} = \frac{10(n+1)}{100}

Substitute 14 for n

P_{10} = \frac{10(14+1)}{100}

P_{10} = \frac{10(15)}{100}

Open the bracket

P_{10} = \frac{10 * 15}{100}

P_{10} = \frac{150}{100}

P_{10} = 1.5th\ item

This means that the 1.5th item is P_{10}

And this falls between the 1st and 2nd item and is calculated as thus;

P_{10} = 1.5th\ item

Express 1.5 as 1 + 0.5

P_{10} = (1 +0.5)\ th\ item

P_{10} = 1^{st}\ item +0.5(2^{nd} - 1^{st}) item

From the given data; 1st\ item = 0.1 and 2nd\ item = 0.1

P_{10} = 1^{st}\ item +0.5(2^{nd} - 1^{st}) item becomes

P_{10} =0.1 +0.5(0.1 - 0.1)

P_{10} =0.1 +0.5(0)

P_{10} =0.1 +0

P_{10} =0.1

3 0
3 years ago
Find the volume of the rectangular prism.<br>1<br>6 cm<br>32<br>cm​
Assoli18 [71]

Answer:

192 centimeters.

Explanation:

V= length x width x height

6 0
3 years ago
What is unique about the TODAY and NOW functions?
Degger [83]

Answer:

The formula does not require arguments.

Explanation:

One of the programs or software that runs on a computer is Microsoft Office programs. One of these programs is called Microsoft Excel. It is a spreadsheet program where calculations can be made, graphs, diagrams can be plotted and drawn as well.

In other to utilize Microsoft Excel properly, we make use of what we call FUNCTIONS. Functions in Microsoft Excel are defined as formulas, that have already been prepared or created before hand in the Microsoft Excel program so that we can be able to used Microsoft Excel properly and efficiently. Functions may or may not require ARGUMENTS to carry out necessary calculations.

An ARGUMENT is a number or variable that functions require to carry out or do their calculations.

Examples of the functions found in Microsoft Excel are the TODAY and NOW functions. These two functions are used in spreadsheets on Microsoft Excel with regards to Date and Time.

TODAY function is used to give us or update the current or present date while the NOW function gives us or updated the current date and time.

The uniqueness or similarities between the TODAY and NOW functions is that their formula do not require arguments.

3 0
3 years ago
Read 2 more answers
8.11 LAB: Count characters - functions Write a program whose input is a character and a string, and whose output indicates the n
Shkiper50 [21]

Answer:

#include<iostream>

using namespace std;

int CountCharacters(char userChar, const string inputstr){

   int k = 0;

   int iter = 0;

   for (iter = 0; iter < inputstr.size(); iter++){

       if (inputstr[iter] ==  userChar){

           ++k;        }}

   return k;}

int main(){

   string str;

   char userChar[1];

   cout<<"Char: ";    cin>>userChar;

   cin.ignore();

   cout<<"String: ";   getline(cin, str);

   cout<<CountCharacters(userChar[0],str);

   return 0;}

Explanation:

Written in C++:

The function is defined here:

int CountCharacters(char userChar, const string inputstr){

This initializes a count variable k to 0

   int k = 0;

This initializes an iterating variable iter to 0

   int iter = 0;

This iterates through the characters of the string being passed to the function

   for (iter = 0; iter < inputstr.size(); iter++){

This checks for matching characters

       if (inputstr[iter] ==  userChar){

If found,  k is incremented by 1

           ++k;        }}

This returns the total count

   return k;}

The main begins here

int main(){

This declares a string variable

   string str;

This declares a character variable

   char userChar[1];

This gets input for the character variable

   cout<<"Char: ";    cin>>userChar;

This lets the user get another input

   cin.ignore();

This gets input for the string variable

   cout<<"String: ";   getline(cin, str);

This calls the function and return the count of character in the string

   cout<<CountCharacters(userChar[0],str);

6 0
3 years ago
In order to consolidate your theoretical knowledge into technique and skills with practical and applicational value, you will us
Arisa [49]

Answer:

Check the explanation

Explanation:

Lasso: R example

To run Lasso Regression you can re-use the glmnet() function, but with the alpha parameter set to 1.

# Perform 10-fold cross-validation to select lambda --------------------------- lambdas_to_try <- 10^seq(-3, 5, length.out = 100) # Setting alpha = 1 implements lasso regression lasso_cv <- cv.glmnet(X, y, alpha = 1, lambda = lambdas_to_try, standardize = TRUE, nfolds = 10) # Plot cross-validation results plot(lasso_cv)

Best cross-validated lambda lambda_cv <- lasso_cv$lambda.min # Fit final model, get its sum of squared residuals and multiple R-squared model_cv <- glmnet(X, y, alpha = 1, lambda = lambda_cv, standardize = TRUE) y_hat_cv <- predict(model_cv, X) ssr_cv <- t(y - y_hat_cv) %*% (y - y_hat_cv) rsq_lasso_cv <- cor(y, y_hat_cv)^2 # See how increasing lambda shrinks the coefficients -------------------------- # Each line shows coefficients for one variables, for different lambdas. # The higher the lambda, the more the coefficients are shrinked towards zero. res <- glmnet(X, y, alpha = 1, lambda = lambdas_to_try, standardize = FALSE) plot(res, xvar = "lambda") legend("bottomright", lwd = 1, col = 1:6, legend = colnames(X), cex = .7)

Kindly check the Image below.

5 0
3 years ago
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