Answer:
fully simplified answer: x^2-2x+8
Step-by-step explanation:
(x^2-3x+2)-1(3x^2-5x-1)=
x^2-3x+2-3x^2+5x+1=
x^2-3x^2-3x+5x+2+1=
-2x^2+2x+3
The answer to this problem would be B because your going up by 6
The range of a function is the set of all values that it can take when its independent variable takes values on the domain.
On the other hand, the range of a function is the domain of its inverse function, if that inverse exists, and vice-versa: the domain of a function is the range of its inverse function, if that inverse exists.
In the case of the given equation:

The inverse function exists since the function is linear, and it can be found by isolating <em>x</em>:

If the range of the original function is the set given by the number {