Answer:
Network, vendor, and bill.
Explanation:
Network convergence is a term used in communication networking that describes the productive synergy among telephone, video, and data transmission using a single network, vendor, and a bill. It enables usage of numerous devices and numerous services with single network, vendor, and bill.
Hence, in this case, it can be concluded that, Network convergence refers to using a single network, single vendor, and single bill.
Answer:
retupmoc
Explanation:
1.) Anwser will be retupmoc
because
public static String mysteryString(String s){
if(s.length() == 1){
return s;
}
else{
return s.substring(s.length() -1) + mysteryString(s.substring(0, s.length()-1));
}
}
In this program input is "computer" . So the function mysteryString(String s) it does
return s.substring(s.length() -1) + mysteryString(s.substring(0, s.length()-1));
so when it enters the first time ??s.substring(s.length() -1) and it will be give you 'r' then it calls the function recursively by reducing the string length by one . So next time it calls the mysteryString function with string "compute" and next time it calls return s.substring(s.length()-1)? + mysteryString(s.substring(0,s.length-1)) so this time it gives "e" and calls the function again recursively . It keeps on doing till it matched the base case.
so it returns "retupmoc".
// Variable to keep track of array size
int length = 0;
// Array itself
int array[] = {};
// while loop will take input in the array until a negative number is entered
while(input>=0){
stdin = new Scanner(System.in);
array[length] = stdin;
length +=1;
}
// int variable to terminate while loop
int i =0;
// keep track of index of output array
int y =0;
while(arr[i] != length){
// making output array
int output[]={}; bool flag;
// put the element in out put array considering if it the desired one
output[y] = array [i];
// Now check if it was the desired?
for(int z=1;z<=length;z++){
if(array[i+z]!=output[y]){
flag = true;
}
else
{
output[y]=0;
y+=1;
}
if(array[i+z+1]=output[y] && flag == true){
output[y] = array[i];
y+=1;
}
}
//output the array
for(int o=0;o<y;o++)
System.out.println(output[o];
Answer:
"Deadlock" is the right solution.
Explanation:
- A deadlock seems to be a circumstance where certain (two) computer algorithms that share a similar resource essentially prohibit each other during manipulating the asset, leading to both programs withdrawing to operate.
- This occurs when multiple transfers or transactions block everyone by maintaining locks onto assets that every other activity also needs.
So that the above is the correct answer.