The complete program is to define a boolean method that returns true if all elements of an array are negative, or return false, if otherwise
The method in java, where comments are used to explain each line is as follows:
//This defines the method
public static boolean chkNegative (double[] myArr) {
//This initializes a boolean variable
boolean isNeg = true;
//This iterates through the array
for (int i = 0; i < myArr.length; i++) {
//If the array element is 0 or positive
if (myArr[i] >= 0) {
//Then the boolean variable is set to false
isNeg = false;
//And the loop is exited
break;
}
}
//This returns true or false
return isNeg;
}
Read more about boolean methods at:
brainly.com/question/18318709
Answer:
Explanation:
The object-oriented paradigm; The compilation process Comments; Library inclusions; Program-level definitions; Function prototypes;
The main program; Function definitions Naming conventions; Local and global variables; The concept of a data type;
Integer types; Floating-point types; Text types; Boolean type; Simple input and
output Precedence and associativity; Mixing types in an expression; Integer division and
the remainder operator; Type casts; The assignment operator; Increment and
decrement operators; Boolean operators
The answer is Clip Art
Clip art is a collection of pictures or images that are either built-in or can be imported into a document. These pictures may either be vector graphics or raster graphics. Clip art gallery is typically organized into categories such as objects, people, nature, and many more. They can be anywhere between a few images to thousands of them.
September 1983 hope this helps u good luck
Answer:
The output streams to this question is "output.print(message)".
Explanation:
The description of the following can be given as:
- In the given question it is define a string datatype variable that is "message".
- Then we create a reference variable of PrintWriter class that is "output" and call string type variable that is message by the use of the print function we print message.