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prohojiy [21]
2 years ago
9

18⅔ ÷ ⅔ how many children are there?​

Mathematics
1 answer:
kiruha [24]2 years ago
4 0
The answer is 28

Explanation:


18⅔ ÷ ⅔

= 56/3 ÷ 2/3
= 56/3 x 3/2

= 56/2

=28
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Brrunno [24]

\frac{8 + x}{2}

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3 years ago
Read 2 more answers
a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
Tresset [83]

Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

M = \frac{1}{2}(Lower + Upper)

Where

Lower \to Lower class interval

Upper \to Upper class interval

So, we have:

Class 63-65:

M = \frac{1}{2}(63 + 65) = 64

Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

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Step-by-step explanation:

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Sloan [31]

Answer:

Line d : y = -3x - 3

Line e : y = -3x - 2

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Step-by-step explanation:

Given that,

The slope of each line is -3.

Now,

We know that,

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Now,

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Ellie puts 35 quarter into stacks with the same number of quarter in each stack
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Answer:

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Step-by-step explanation:

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