Answer:
45 degrees for 8
135 degrees for 9
48 for 10
Yes a square is a rectangle
Next ones.
Sut = 21 becuase x=5
7
Step-by-step explanation:
Last one:
x^2 + 8 = 3x + 36
- 8 - 8
x^2 = 3x + 28
-3x -3x
x^2 - 3x = 28
(x · x) - 3x = 28.
This was were a little guess work was used,
I found that any number lower than 7 is less than 28 when pluged into x and any above is higher.
Hence x = 7
So
x^2 + 8 = 7^2 + 8
7 x 7 = 49. 49 + 8 = 57.
and
3x+36 = 7 x 3 + 36
7x3 = 21. 21 + 36 = 57.
Both lines are equal so x is indeed 7.
The RSTU rectangle
3x+6 = 5x-4
+4 +4
3x+10 = 5x
-3x -3x
10 = 2x
10/2 = 5
5 = x or x = 5
plug it in now
3 x 5 = 15. 15 + 6 = 21
and
5 x 5 = 25. 25 - 4 = 21
so x = 5
8-10
QRS = 45 degrees because bisects the square with a diagonal line from corner to corner
PTQ is a 135 degrees because it is wider than a 90 degrees angle and meets both upper corner from the middle of the square making it 135 degrees.
SQ = 48 because RT = 24 and RT is half the length of SQ meaning its length would be 48
Or
SQ= 24 degrees because RT = 24 and if RT was to continue on the line it is on it will reach the length of SQ.
6.5 x 10 to the 3rd power
remember the base must be less than 10 and greather or equal to 1
Answer:
{-3/2, 4}
Step-by-step explanation:
Use synthetic division here. If the remainder is 0, then the divisor is a root or solution.
Here we have x = -4. Perform the synthetic division as follows:
-4 4 -10 -24
-16 108
------------------------------
4 -26 84 The remainder is 84, which tells us -4 is NOT
a root/solution.
Try -3/2 as divisor this time:
-3/2 4 -10 -24
-6 24
------------------------------
4 -16 0 Remainder is 0, so -3/2 is a solution
Show in the same manner that 4 is a solution also. Or determine whether x - 4 satisfies 4x - 16 = 0 (it does).
B. Because 5 t 5 t 4 t 4 equals 18
Answer:
The mean of the sampling distribution of x is 0.5 and the standard deviation is 0.083.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For the population, we have that:
Mean = 0.5
Standard deviaiton = 0.289
Sample of 12
By the Central Limit Theorem
Mean = 0.5
Standard deviation 
The mean of the sampling distribution of x is 0.5 and the standard deviation is 0.083.
