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sammy [17]
2 years ago
6

What is the product of (y + 3) and (7y – 1)?

Mathematics
1 answer:
Lorico [155]2 years ago
4 0

Answer: =7y^2+20y−3

Step-by-step explanation:

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How do I simplify this exponent problem???
Nikolay [14]

Hello from MrBillDoesMath!

Answer:

(3/4) a^(-5)b^(-3)c^2


Discussion:  

(18 a^-3b^2c^6)/ (24 a^2b^5c^4) =

(18/24) a^ (-3-2) b^(2-5) c^(6-4) =

                  as  a^-3/a^-2 = a ^ (-3-2) = a^(-5), for examples

(3/4) a^(-5)b^(-3)c^2


Thank you,

MrB

8 0
3 years ago
Which of the tables represents a function?
Damm [24]
Input is domain and output is co-domain.
An expression is said to be a function if for every input, there is only one output. In table B, for every input, you get different outputs. Therefore, table B is a function. 
3 0
3 years ago
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The perimeter of a basketball court is 84 meters and the length is 6 meters longer than twice the width. what are the length and
Colt1911 [192]
The length is 30 meters and the width is 12 meters. 
3 0
3 years ago
A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall
Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is \frac{1}{5}

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

\text{Probability}=\frac{5}{25}

\text{Probability}=\frac{1}{5}

5 0
3 years ago
Can someone help me this question please?
pashok25 [27]
Larger number is 32 because if u take 48 minus 16 u get your anwser
5 0
3 years ago
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