Answer:
1 . The stage on the first meiotic division when the homologous chromosomes move to opposite poles but the sister chromatids remain together
: b. Anaphase I
2 . The stage in the second meiotic division where sister chromatids migrate to opposite poles
: c. Anaphase II
3 . A structure on the chromosome that holds a pair of chromatids together during replication
: f. centromere
4 . A double-stranded chromosome following replication attached by a centromere
: d. chromatid
5 . A condition where non-sister chromatid of homologous chromosomes exchange genes
: e. crossing over
6 . The stage in the first meiotic division where the homologous chromosomes line up as a pair
: a. Metaphase I
7 . The stage in the second meiotic division where the chromatid pair lines up at the equator of the cell: g. Metaphase II
Explanation:
DNA replication occurs during the S phase of the interphase of the cell cycle. The replicated DNA molecules are accommodated in two sister chromatids of a chromosome that are held together by a centromere.
During prophase I, the chromatids of a homologous chromosome pair exchange a genetic segment. This process is called crossing over. It generates recombinant chromatids with new combinations of genes.
Metaphase I of meiosis I includes the alignment of homologous pairs of chromosomes at the cell's equator. This is followed by separation and movement of homologous chromosomes to the opposite poles of the cell during anaphase I.
Metaphase II of meiosis II includes the alignment of individual chromosomes, each with two sister chromatids, on the cell's equator. During anaphase II, splitting centromere separates the sister chromatids which then move to the opposite poles of the cell.
Answer:
<em>Nitrogen</em><em> </em><em>dioxide</em><em> </em><em>is </em><em>an </em><em>irritant </em><em>gas,</em><em> </em><em>which </em><em>at </em><em>high </em><em>concentration</em><em> </em><em>cause </em><em>inflammation </em><em>of </em><em>the </em><em>airways.</em><em> </em><em>.</em><em>.</em><em>.</em><em> </em><em>Nox </em><em>gases </em><em>react</em><em> </em><em>to </em><em>form </em><em>smog </em><em>and </em><em>acid </em><em>rain </em><em>as </em><em>well </em><em>as </em><em>being </em><em>central </em><em>to </em><em>the </em><em>formation</em><em> </em><em>of </em><em>fine </em><em>particles </em><em>and </em><em>ground</em><em> </em><em>level </em><em>ozone,</em><em> </em><em>both </em><em>of </em><em>which</em><em> </em><em>are</em><em> </em><em>associated</em><em> </em><em>with </em><em>adverse </em><em>health</em><em> </em><em>effects.</em>
Answer:
50%
Explanation:
let me know if im right tho
He found a nuclear structure (cells) in plants by looking through a microscope
Answer:
The prolonged electrical depolarization of cardiac muscle cells -that occurs during contraction- is due primarily to the persistent influx of calcium ion
Explanation:
The action potential of the heart muscle is longer with respect to skeletal muscle (around 300 milliseconds), and this is due to the activity of calcium (Ca⁺⁺ ) in the intracellular compartment.
The initial depolarization of cardiac muscle fiber depends on the entry of sodium (Na⁺) into the cell. However, for the action potential to occur and be maintained, Ca⁺⁺ must increase its cytoplasmic levels, which depends on:
- The increase in intracellular sodium induces the release of Ca⁺⁺ from the sarcoplasmic reticulum.
- Calcium entry from the extracellular space through the voltage dependent Ca⁺⁺ channels.
- The entry of extracellular Ca⁺⁺ causes the release of more Ca⁺⁺ ions by the sarcoplasmic reticulum, further increasing its intracellular concentration.
This is how the ion that guarantees the duration of the action potential of the cardiac muscle cell is the Ca⁺⁺.
Learn more:
Calcium, sodium and cardiac muscle cells brainly.com/question/4473795
