Answer:
Step-by-step explanation:
This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):
![sin^{-1}[sin(2x+30)]=sin^{-1}(1)](https://tex.z-dn.net/?f=sin%5E%7B-1%7D%5Bsin%282x%2B30%29%5D%3Dsin%5E%7B-1%7D%281%29)
On the left, the inverse sin "undoes" or cancels the sin, leaving us with
2x + 30 = sin⁻¹(1)
The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:
2x + 30 = 90 and
2x = 60 so
x = 30
You're welcome!
18x-8x2=0
Two solutions were found :
x = 9/4 = 2.250
x = 0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
18x - 23x2 = 0
Divide the second term by the first to get the common ratio.
Answer:
y intercept is -11
slope= -5/2
Step-by-step explanation:
slope is a negative one with points on x(-4.4) and x(-11)